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September 16, 2011 How to filter an array so the result is an array again? | ||||
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The standard library std.algorithm is based on Range. So if
a = [1, 2, 3, 4];
auto r = filter!("a < 2")(a);
Here, r is a range.
How about I want an new array? Is there any easy way to convert the
result to array?
If we have to do like:
int[] b;
for (v; r) {
b ~= v;
}
Then maybe it is easier to not use filter at all as:
int [] b;
for (v; a) {
if (v < 2) b ~= v;
}
Thanks a lot.
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September 16, 2011 Re: How to filter an array so the result is an array again? | ||||
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Posted in reply to Cheng Wei | Sorry, the 'for' should be 'foreach'. | |||
September 16, 2011 Re: How to filter an array so the result is an array again? | ||||
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Posted in reply to Cheng Wei | On Friday, September 16, 2011 04:04:39 Cheng Wei wrote:
> The standard library std.algorithm is based on Range. So if
> a = [1, 2, 3, 4];
> auto r = filter!("a < 2")(a);
>
> Here, r is a range.
> How about I want an new array? Is there any easy way to convert the
> result to array?
>
> If we have to do like:
> int[] b;
> for (v; r) {
> b ~= v;
> }
>
> Then maybe it is easier to not use filter at all as:
> int [] b;
> for (v; a) {
> if (v < 2) b ~= v;
> }
Use std.array.array.
auto a = [1, 2, 3, 4];
auto r = array(filter!"a < 2"(a));
- Jonathan M Davis
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