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How do I pass a template type as parameter?
Apr 16, 2019
Machine Code
Apr 16, 2019
Adam D. Ruppe
Apr 16, 2019
Machine Code
April 16, 2019
Gravatar of Machine CodePosted by Machine CodeReply
Machine Code
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I've tried those syntaxes:

void f(appender!string buffer) { }
void f(A = appender)(A!string buffer) { }

but no luck... how do I do that?
April 16, 2019
Gravatar of Adam D. RuppePosted by Adam D. Ruppe
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Adam D. Ruppe
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On Tuesday, 16 April 2019 at 21:07:51 UTC, Machine Code wrote:
> void f(appender!string buffer) { }

appender isn't a type, it is a helper function that returns a type called Appender:

http://dpldocs.info/experimental-docs/std.array.appender.1.html

http://dpldocs.info/experimental-docs/std.array.Appender.html



So try like `void f(Appender!string buffer) {}`
April 16, 2019
Gravatar of Machine CodePosted by Machine Code
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Machine Code
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On Tuesday, 16 April 2019 at 21:24:54 UTC, Adam D. Ruppe wrote:
> On Tuesday, 16 April 2019 at 21:07:51 UTC, Machine Code wrote:
>> void f(appender!string buffer) { }
>
> appender isn't a type, it is a helper function that returns a type called Appender:
>
> http://dpldocs.info/experimental-docs/std.array.appender.1.html
>
> http://dpldocs.info/experimental-docs/std.array.Appender.html
>
>
>
> So try like `void f(Appender!string buffer) {}`

I see. Thank you!