The code:
    void    go    (ulong    recNum)
    {    assert (buf[0] == (fh.sizeof + recNo * buf.length) & 0x7f);
        if    (dirty)
yields the error message:
ells$ dmd test.d
test.d(78): Error: buf[0] == fh.sizeof + recNo * buf.length must be parenthesized when next to operator &

And I'll swear it looks parenthesized to me.

    void    go    (ulong    recNum)
    {    ubyte    tst    =    (fh.sizeof + recNo * buf.length) & 0x7f;
        assert (buf[0] == tst);
        if    (dirty)

compiles without error.

Any idea what's going on?

On Thursday, 23 October 2014 at 18:15:26 UTC, Charles Hixson via
Digitalmars-d-learn wrote:
> The code:
>     void    go    (ulong    recNum)
>     {    assert (buf[0] == (fh.sizeof + recNo * buf.length) & 0x7f);
>         if    (dirty)
> yields the error message:
> ells$ dmd test.d
> test.d(78): Error: buf[0] == fh.sizeof + recNo * buf.length must be parenthesized when next to operator &
>
> And I'll swear it looks parenthesized to me.

The expression is of the form `a == b & c`. You must parenthesize
either `a == b` or `b & c`, making it `(a == b) & c` or `a == (b
& c)`.