Suppose I've got a function that is conditional on a type:

    void foo(T)(/* input vars */) { ... }

How could I print out using writeln the name of that type?  So that if I call

    foo!double(...);

... I would see:

    Today, Michael, I'm going to be a double!

... whereas if I give it,

    foo!uint(...);

I'd see

    Today, Michael, I'm going to be a uint!

and so on.  Ideally this should also work for complex data types such as structs, classes, etc.

On Thursday, 4 July 2013 at 14:46:36 UTC, Joseph Rushton Wakeling wrote:
> ...

Each has own disadvantages, chose one ;)

T.stringof // simple & reliable, won't work for function aliases
__traits(identifier, T) // only symbols
std.traits.fullyQualifiedName!T // issues with templated types, includes module/package into name

On Thursday, 4 July 2013 at 14:51:21 UTC, Artur Skawina wrote:
> On 07/04/13 16:46, Joseph Rushton Wakeling wrote:
>> Suppose I've got a function that is conditional on a type:
>> 
>>     void foo(T)(/* input vars */) { ... }
>> 
>> How could I print out using writeln the name of that type?  So that if I call
>> 
>>     foo!double(...);
>> 
>> ... I would see:
>> 
>>     Today, Michael, I'm going to be a double!
>
>     writeln("Today, Michael, I'm going to be a "~T.stringof~"!")
>
> artur

What he said. Or if you don't even have T, use "typeof(t).stringof".

This also works in pragma msg:
pragma(msg, T.stringof);