for(uint y=0; y<10; ++y){
	auto m = new Mutex();
	writeln(&m);
}

run:

7F66E5A05CF8
7F66E5A05CF8
7F66E5A05CF8
7F66E5A05CF8
7F66E5A05CF8
7F66E5A05CF8
7F66E5A05CF8
7F66E5A05CF8
7F66E5A05CF8
7F66E5A05CF8

As I understand it, all the time return one object
But:

auto m = new Mutex();
writeln(&m);
auto m1 = new Mutex();
writeln(&m1);

run:

7FCF60698CF0
7FCF60698CF8

On Sunday, 23 December 2012 at 19:43:54 UTC, Shadow_exe wrote:
> for(uint y=0; y<10; ++y){
> 	auto m = new Mutex();
> 	writeln(&m);
> }

That's the address of the local variable. The object it points to is somewhere else.

An Object in D is more like an Object* in C++.

Object* o = new Object();
&o == 0
o == 1

o = new Object();
&o == 0 // the local variable is still in the same place
o == 2 // but it now points to a new object

On 12/23/12, Shadow_exe <shadow_exe@ukr.net> wrote:
> for(uint y=0; y<10; ++y){
> 	auto m = new Mutex();
> 	writeln(&m);
> }

Use writeln(cast(void*)m) to get the address of the object, otherwise
you're writing the address of the reference (which each time refers to
a different object).

Yes, thank you!
Tired apparently, I need to rest...