I need to create a non-dynamic array like this

void f(int x)
{
int[x] my_array;
...

this does not compile as x value needs to be known at compile time. The closest to this I can get is:

void f(int x)
{
int[] my_array;
my_array.length=x;

but I don't really need a dynamic array as length is not going to change inside f.

What is the best way to do this?

Thanks in advance

Miguel L wrote:

> I need to create a non-dynamic array like this
>
> void f(int x)
> {
> int[x] my_array;
> ...
>
> this does not compile as x value needs to be known at compile time. The closest to this I can get is:
>
> void f(int x)
> {
> int[] my_array;
> my_array.length=x;
>
> but I don't really need a dynamic array as length is not going to change inside f.
>
> What is the best way to do this?
>
> Thanks in advance

for simple cases you can use `alloca()`. it is fairly low-level, but does it's job.

but if your array is really big, or contains types with dtors, you'd better stick with `new` (or setting length). you can also put `scope(exit) delete my_array;` after declaration, so array will be destroyed on function exit. `delete` is... slightly deprecated ;-) (i.e. not recommented for wide use), but works, and will call dtors for you.

On Tuesday, 11 July 2017 at 08:23:02 UTC, Miguel L wrote:
> I need to create a non-dynamic array like this
>
> void f(int x)
> {
> int[x] my_array;
> ...
>
> this does not compile as x value needs to be known at compile time. The closest to this I can get is:
>
> void f(int x)
> {
> int[] my_array;
> my_array.length=x;
>
> but I don't really need a dynamic array as length is not going to change inside f.
>
> What is the best way to do this?
>
> Thanks in advance
Another approach would be to use a template function:

----
void f(int x)()
{
    int[x] array;
}

void main()
{
    f!42;
}
----