Hello,
Just get to my point to save time:

1.retro:

void testRetro()
{
int[] arr=[1,2,3,4,5];
auto retArr=retro(arr);
for(int i=0;i<retArr;i++)
writef("%d ",retArr[i]);
}
void main()
{
testRetro;
}

output:
0 0 5 4 3 //not 5 4 3 2 1 ?what's wrong here?

2.Continue to #1,In the source:
static if (isRandomAccessRange!(R) && hasLength!(R))
        ref ElementType!(R) opIndex(uint n)
        {
            return _input[_input.length - n + 1];
        }
Per my understanding,the above will return the nth element of _input in reverse order. I try to count my fingers with length-n+1 but cannot get a correct result.

3. About isInfinte:
template isInfinite(Range)
{
    static if (isInputRange!(Range) && is(char[1 + Range.empty]))
        enum bool isInfinite = !Range.empty;
    else
        enum bool isInfinite = false;
}
In the is expression is(char[1+ Range.empty]),below is my understanding;

Step 1:
is(char[1+Range.empty]) actually returns is(char[1+Range.empty?0:1])
Step 2:
But what does this help with determining whether Range is infinite or not?say char[1+0],char[1+1]?

Any help would be much much appreciated.

Regards,
Sam

On Wed, 17 Jun 2009 00:04:51 -0400, Sam Hu <samhudotsamhu@gmail.com> wrote:

>Hello,
>Just get to my point to save time:
>
>1.retro:
>
>void testRetro()
>{
>int[] arr=[1,2,3,4,5];
>auto retArr=retro(arr);
>for(int i=0;i<retArr;i++)
>writef("%d ",retArr[i]);
>}
>void main()
>{
>testRetro;
>}
>
>output:
>0 0 5 4 3 //not 5 4 3 2 1 ?what's wrong here?
>
>2.Continue to #1,In the source:
>static if (isRandomAccessRange!(R) && hasLength!(R))
>        ref ElementType!(R) opIndex(uint n)
>        {
>            return _input[_input.length - n + 1];
>        }
>Per my understanding,the above will return the nth element of _input in reverse order. I try to count my fingers with length-n+1 but cannot get a correct result.
>
>3. About isInfinte:
>template isInfinite(Range)
>{
>    static if (isInputRange!(Range) && is(char[1 + Range.empty]))
>        enum bool isInfinite = !Range.empty;
>    else
>        enum bool isInfinite = false;
>}
>In the is expression is(char[1+ Range.empty]),below is my understanding;
>
>Step 1:
>is(char[1+Range.empty]) actually returns is(char[1+Range.empty?0:1])
>Step 2:
>But what does this help with determining whether Range is infinite or not?say char[1+0],char[1+1]?
>
>Any help would be much much appreciated.
>
>Regards,
>Sam

3. This is a (hackish) way to detect if Range.empty's value is statically known. Infinite ranges must define a boolean 'empty' member that evaluates at compile time to false.

Probably, there should be a more generic way to do it. Something like isCT(alias expression) template. I kinda have one but it doesn't work in all cases due to a compiler bug.

On Wed, 17 Jun 2009 00:04:51 -0400, Sam Hu <samhudotsamhu@gmail.com> wrote:

>Hello,
>Just get to my point to save time:
>
>1.retro:
>
>void testRetro()
>{
>int[] arr=[1,2,3,4,5];
>auto retArr=retro(arr);
>for(int i=0;i<retArr;i++)
>writef("%d ",retArr[i]);
>}
>void main()
>{
>testRetro;
>}
>
>output:
>0 0 5 4 3 //not 5 4 3 2 1 ?what's wrong here?
>
>2.Continue to #1,In the source:
>static if (isRandomAccessRange!(R) && hasLength!(R))
>        ref ElementType!(R) opIndex(uint n)
>        {
>            return _input[_input.length - n + 1];
>        }
>Per my understanding,the above will return the nth element of _input in reverse order. I try to count my fingers with length-n+1 but cannot get a correct result.
>

Looks like a bug. The fix is easy:

    static if (isRandomAccessRange!(R) && hasLength!(R))
        ref ElementType!(R) opIndex(uint n)
        {
            return _input[_input.length - n - 1];
        }

or

    static if (isRandomAccessRange!(R) && hasLength!(R))
        ref ElementType!(R) opIndex(uint n)
        {
            return _input[_input.length - (n + 1)];
        }


>3. About isInfinte:
>template isInfinite(Range)
>{
>    static if (isInputRange!(Range) && is(char[1 + Range.empty]))
>        enum bool isInfinite = !Range.empty;
>    else
>        enum bool isInfinite = false;
>}
>In the is expression is(char[1+ Range.empty]),below is my understanding;
>
>Step 1:
>is(char[1+Range.empty]) actually returns is(char[1+Range.empty?0:1])
>Step 2:
>But what does this help with determining whether Range is infinite or not?say char[1+0],char[1+1]?
>
>Any help would be much much appreciated.
>
>Regards,
>Sam

Max Samukha Wrote:
> 3. This is a (hackish) way to detect if Range.empty's value is statically known. Infinite ranges must define a boolean 'empty' member that evaluates at compile time to false.
> 
> Probably, there should be a more generic way to do it. Something like isCT(alias expression) template. I kinda have one but it doesn't work in all cases due to a compiler bug.

Thank you so much for all your help!

Regards,
Sam