July 03, 2013 Re: Stop to! rounding? | ||||
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Posted in reply to Marco Leise | On Wed, Jul 03, 2013 at 07:56:28PM +0200, Marco Leise wrote: > Am Tue, 2 Jul 2013 22:21:52 -0700 > schrieb "H. S. Teoh" <hsteoh@quickfur.ath.cx>: > > > On Tue, Jul 02, 2013 at 10:14:33PM -0700, Ali Çehreli wrote: [...] > > > import std.stdio; > > > import std.conv; > > > > > > void main() > > > { > > > auto a = to!double("151.42499"); > > > writefln("%.60f", a); > > > } > > > > I wouldn't write it like that; IMO it's better to write: > > > > writefln("%.*f", double.dig, a); > > > > So that you don't give the wrong impression that there are more digits than are actually there. Using double.dig also lets you see all the digits that *are* there, not a rounded value, that the OP was complaining about. > > > > > > T > > > > *f ? I didn't know that you can format the format string like that. Thanks for the tip. [...] Basically, it's a wildcard precision. Usually you'd write %.5f for 5 digits following the decimal point, for example, but that requires hardcoding the integer literal into the format string. In some cases you need it to be variable, so '*' was introduced as a stand-in for the next item in the argument list. So writefln("%.*f", 5, a) is equivalent to writefln("%.5f", a). The wildcard * can also be used in the field-width, so writefln("%*.*f", 5, 2, 1) is equivalent to writefln("%5.2f", 1). This isn't D's innovation, BTW, the * width/precision specifier is defined in the same way in C's printf(). T -- He who does not appreciate the beauty of language is not worthy to bemoan its flaws. |
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