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October 31, 2013 howto make a function get a types form compilte-time-parameters AND from the arguments ? | ||||
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(this is my first post so please alert me to any breaches of forum etiquette) Hello, I have a problem with a helper function I'm writeting. T[] makeArray(T,U)(immutable U[] paramArray) { T[] result; foreach (param;paramArray) { result ~= T(param); } return result; } and I would like not to take the compile-time-parameter U but insead infering it form the argumet. is it possible ? and if. how ? ---- Uplink_Coder |
October 31, 2013 Re: howto make a function get types form compile-time-parameters AND from arguments ? | ||||
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Posted in reply to Uplink_Coder | Maybe I shuold be more specific : for now It's: T[] arr = makeArray!(T,U)([some,instances,of,U]); but I would like it to be: auto arr = makeArray!(T)([some,instances,of,U]); |
October 31, 2013 Re: howto make a function get types form compile-time-parameters AND from arguments ? | ||||
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Posted in reply to Uplink_Coder | On Thursday, 31 October 2013 at 10:18:25 UTC, Uplink_Coder wrote:
>
> Maybe I shuold be more specific :
> for now It's:
> T[] arr = makeArray!(T,U)([some,instances,of,U]);
>
> but I would like it to be:
>
> auto arr = makeArray!(T)([some,instances,of,U]);
void foo(T,U)(U arg){}
int a;
foo!(double)(a); //U is inferred as int
void bar(T,U)(U[] arg){}
long[] b;
foo!(double)(b); //U is in inferred as long
However, be aware that you can't pass mutable or const data as an immutable argument. Perhaps the signature that would work better for you would be
T[] makeArray(T,U)(const U[] paramArray)
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October 31, 2013 Re: howto make a function get types form compile-time-parameters AND from arguments ? | ||||
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Posted in reply to John Colvin | by changeing T[] makeArray(T,U)(immutable U[] paramArray) into T[] makeArray(T,U)(const U paramArray) if (isAggregateType!(U) || is Array!(U)) everything works perfectly Thanks very much --- Uplink_Coder |
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