October 14, 2005
http://digitalmars.com/d/builtin.html

at the bottom: "? It's no contest"
October 14, 2005
In other words, this:

c = (6 + 2i - 1 + 3i) / 3i;

Is so many levels better than:

c = (complex!(double)(6,2) + complex!(double)(-1,3)) / complex!(double)(0,3);

That there can't even be any sort of contest between them.  The first is simply, inarguably, better.  Or, at least, that's what it says.  I tend to agree.

-[Unknown]


> http://digitalmars.com/d/builtin.html
> 
> at the bottom: "? It's no contest"
October 14, 2005
dennis luehring wrote:
> http://digitalmars.com/d/builtin.html
> 
> at the bottom: "? It's no contest"

If the placement of the '?' on the start of the line confused you, think about it like this:
------
Isn't:

	c = (6 + 2i - 1 + 3i) / 3i;
	
far preferable than writing:
	c = (complex!(double)(6,2) + complex!(double)(-1,3)) / complex!(double)(0,3);
	
? It's no contest
----

it's basically saying:
-----
Isn't X far preferable than writing Y ? It's no contest
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