Thread overview
"".dup is null
May 04, 2009
Qian Xu
May 04, 2009
Qian Xu
May 04, 2009
Qian Xu
May 04, 2009
Georg Wrede
May 04, 2009
Hi All,

The following code will throw an exception:
  char[] s;
  assert( s.dup  is null); // OK
  assert("".dup !is null); // FAILED

"".dup is expectly also an empty string. Is this a compiler bug?

--Qian


May 04, 2009
On Mon, 04 May 2009 09:46:57 -0400, Qian Xu <quian.xu@stud.tu-ilmenau.de> wrote:

> Hi All,
>
> The following code will throw an exception:
>   char[] s;
>   assert( s.dup  is null); // OK
>   assert("".dup !is null); // FAILED
>
> "".dup is expectly also an empty string.
> Is this a compiler bug?
>

I think you might have a bug?

"".dup is the same as s.dup, not sure why you would expect it to be not-null.

-Steve
May 04, 2009
Steven Schveighoffer wrote:

> On Mon, 04 May 2009 09:46:57 -0400, Qian Xu <quian.xu@stud.tu-ilmenau.de> wrote:
> 
>> Hi All,
>>
>> The following code will throw an exception:
>>   char[] s;
>>   assert( s.dup  is null); // OK
>>   assert("".dup !is null); // FAILED
>>
>> "".dup is expectly also an empty string.
>> Is this a compiler bug?
>>
> 
> I think you might have a bug?
> 
> "".dup is the same as s.dup, not sure why you would expect it to be not-null.
> 
> -Steve

They are not the same. s is null. "" is an empty string. empty string and null are definitely two thing.
May 04, 2009
Steven Schveighoffer wrote:

> I think you might have a bug?
> 
> "".dup is the same as s.dup, not sure why you would expect it to be not-null.
> 
> -Steve

If I have not explained clearly. Here is the full code:

  char[] s;
  assert(s     is null);
  assert(s.dup is null);

  assert(""     !is null); // OK
  assert("".dup !is null); // FAILED

At least the last two lines behave not consistent. Either both are failed, or both are passed.

May 04, 2009
On Mon, 04 May 2009 10:22:49 -0400, Qian Xu <quian.xu@stud.tu-ilmenau.de> wrote:

> Steven Schveighoffer wrote:
>
>> I think you might have a bug?
>>
>> "".dup is the same as s.dup, not sure why you would expect it to be
>> not-null.
>>
>> -Steve
>
> If I have not explained clearly.
> Here is the full code:
>
>   char[] s;
>   assert(s     is null);
>   assert(s.dup is null);
>
>   assert(""     !is null); // OK
>   assert("".dup !is null); // FAILED
>
> At least the last two lines behave not consistent.
> Either both are failed, or both are passed.


OK, your original post was this:

  assert( s.dup  is null); // OK
  assert("".dup !is null); // FAILED


The compiler always returns a null array if you dup an empty array.  The reason being: why allocate memory for something that is zero length?

If anything, the oddity is this line:

assert("" !is null);

But of course, no memory is allocated for literals, so at least needless memory allocation does not occur.

To be consistent, I think assert("" is null); should pass, but it's a minor inconsistency at best.

I usually never compare arrays to null for this reason...

-Steve
May 04, 2009
Steven Schveighoffer wrote:
> On Mon, 04 May 2009 10:22:49 -0400, Qian Xu <quian.xu@stud.tu-ilmenau.de> wrote:
> 
>> Steven Schveighoffer wrote:
>>
>>> I think you might have a bug?
>>>
>>> "".dup is the same as s.dup, not sure why you would expect it to be
>>> not-null.
>>>
>>> -Steve
>>
>> If I have not explained clearly.
>> Here is the full code:
>>
>>   char[] s;
>>   assert(s     is null);
>>   assert(s.dup is null);
>>
>>   assert(""     !is null); // OK
>>   assert("".dup !is null); // FAILED
>>
>> At least the last two lines behave not consistent.
>> Either both are failed, or both are passed.
> 
> 
> OK, your original post was this:
> 
>   assert( s.dup  is null); // OK
>   assert("".dup !is null); // FAILED
> 
> 
> The compiler always returns a null array if you dup an empty array.  The reason being: why allocate memory for something that is zero length?
> 
> If anything, the oddity is this line:
> 
> assert("" !is null);

If I remember correctly, string literals are stored with a null appended, so as to make them easier to use with OS calls, etc. Could it be that "" stores a 1-byte string, consisting with just this null? Then this behavior would be understandable.

> But of course, no memory is allocated for literals, so at least needless memory allocation does not occur.
> 
> To be consistent, I think assert("" is null); should pass, but it's a minor inconsistency at best.
> 
> I usually never compare arrays to null for this reason...
> 
> -Steve
May 04, 2009
On Mon, 04 May 2009 12:09:09 -0400, Georg Wrede <georg.wrede@iki.fi> wrote:

> If I remember correctly, string literals are stored with a null appended, so as to make them easier to use with OS calls, etc. Could it be that "" stores a 1-byte string, consisting with just this null? Then this behavior would be understandable.

Yes, that makes complete sense, thanks.

-Steve