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July 27, 2010 D1->D2 member call syntax regression? | ||||
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In converting some D1 code to D2, I noticed this doesn't seem to work anymore: module mymodule; class Foo() { void bar(string s) {...} void foo() { string str = "hello"; str.bar(); } } In D1 that works fine, but in D2 (2.047) it complains that it can't find "mymodule.bar". That's a bit dissapointing, as I keep hoping member call syntax will eventually get expanded, not reduced. Is this a bug, or is there some reason for it? |
July 27, 2010 Re: D1->D2 member call syntax regression? | ||||
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Posted in reply to Nick Sabalausky | On Tuesday, July 27, 2010 16:25:28 Nick Sabalausky wrote:
> In converting some D1 code to D2, I noticed this doesn't seem to work anymore:
>
> module mymodule;
> class Foo()
> {
> void bar(string s) {...}
>
> void foo()
> {
> string str = "hello";
> str.bar();
> }
> }
>
> In D1 that works fine, but in D2 (2.047) it complains that it can't find "mymodule.bar". That's a bit dissapointing, as I keep hoping member call syntax will eventually get expanded, not reduced. Is this a bug, or is there some reason for it?
It looks more like a bug fix to me given that the first parameter to bar() is the invisible this rather than a string, but since I've never used D1, I certainly can't compare what it does to D2.
- Jonathan M Davis
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July 27, 2010 Re: D1->D2 member call syntax regression? | ||||
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Posted in reply to Nick Sabalausky | It seems to work, on 2.042, and on dmd 2.047: http://ideone.com/dcsK3 Bye, bearophile |
July 28, 2010 Re: D1->D2 member call syntax regression? | ||||
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Posted in reply to bearophile | "bearophile" <bearophileHUGS@lycos.com> wrote in message news:i2nqs5$jss$1@digitalmars.com... > It seems to work, on 2.042, and on dmd 2.047: http://ideone.com/dcsK3 > > Bye, > bearophile That's because my original example accidentally made Foo an uninstantiated class template, so the compiler never bothered to check the semantics... The following fails on 2.046 and 2.042, but works fine on 1.062: class Foo { void bar(string s) {} void foo() { string str = "hello"; str.bar(); } } void main() {} |
July 28, 2010 Re: D1->D2 member call syntax regression? | ||||
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Posted in reply to Nick Sabalausky | "Nick Sabalausky" <a@a.a> wrote in message news:i2o9ev$1e4h$1@digitalmars.com... > "bearophile" <bearophileHUGS@lycos.com> wrote in message news:i2nqs5$jss$1@digitalmars.com... >> It seems to work, on 2.042, and on dmd 2.047: http://ideone.com/dcsK3 >> >> Bye, >> bearophile > > That's because my original example accidentally made Foo an uninstantiated class template, so the compiler never bothered to check the semantics... > > The following fails on 2.046 and 2.042, but works fine on 1.062: > > class Foo { > void bar(string s) {} > void foo() { > string str = "hello"; > str.bar(); > } > } > void main() {} The above also fails on 2.047 |
July 28, 2010 Re: D1->D2 member call syntax regression? | ||||
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Posted in reply to Nick Sabalausky | Nick Sabalausky:
> That's because my original example accidentally made Foo an uninstantiated class template, so the compiler never bothered to check the semantics...
Surely here there is no shortage of ways I can paint myself as a stupid :-)
In Python the () after the class name are optional and they do nothing, so I didn't see them in that little D program :-)
Bye,
bearophile
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July 28, 2010 Re: D1->D2 member call syntax regression? | ||||
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Posted in reply to bearophile | "bearophile" <bearophileHUGS@lycos.com> wrote in message news:i2p4iq$po$1@digitalmars.com... > Nick Sabalausky: >> That's because my original example accidentally made Foo an >> uninstantiated >> class template, so the compiler never bothered to check the semantics... > > Surely here there is no shortage of ways I can paint myself as a stupid > :-) > In Python the () after the class name are optional and they do nothing, so > I didn't see them in that little D program :-) > *I'm* the one that was dumb enough put them there in the first place! And I can't use "extensive Python experience" as an excuse ;) |
July 28, 2010 Still unresolved (Was: D1->D2 member call syntax regression?) | ||||
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Posted in reply to Nick Sabalausky | "Nick Sabalausky" <a@a.a> wrote in message news:i2pvvi$2g83$1@digitalmars.com... > "bearophile" <bearophileHUGS@lycos.com> wrote in message news:i2p4iq$po$1@digitalmars.com... >> Nick Sabalausky: >>> That's because my original example accidentally made Foo an >>> uninstantiated >>> class template, so the compiler never bothered to check the semantics... >> >> Surely here there is no shortage of ways I can paint myself as a stupid >> :-) >> In Python the () after the class name are optional and they do nothing, >> so I didn't see them in that little D program :-) >> > > *I'm* the one that was dumb enough put them there in the first place! And I can't use "extensive Python experience" as an excuse ;) > It still leaves the question though, "Why isn't that working in D2? Bug or legitimate reason?". Jonathan suggested it was deliberate because of the hidden "this" parameter, but I'm not convinced because 1) D1 has the hidden "this" param too, but it handles it just fine, and 2) It's just a syntactical issue, so I don't see how semantics could be a problem unless there's some other change in D2 that causes a conflict or ambiguity with that feature. In any case, the error message seems to indicate that, deliberate or not, it's likely some sort of symbol-lookup/visibility issue. |
July 28, 2010 Re: Still unresolved (Was: D1->D2 member call syntax regression?) | ||||
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Posted in reply to Nick Sabalausky | Nick Sabalausky wrote:
> "Nick Sabalausky" <a@a.a> wrote in message news:i2pvvi$2g83$1@digitalmars.com...
>> "bearophile" <bearophileHUGS@lycos.com> wrote in message news:i2p4iq$po$1@digitalmars.com...
>>> Nick Sabalausky:
>>>> That's because my original example accidentally made Foo an uninstantiated
>>>> class template, so the compiler never bothered to check the semantics...
>>> Surely here there is no shortage of ways I can paint myself as a stupid :-)
>>> In Python the () after the class name are optional and they do nothing, so I didn't see them in that little D program :-)
>>>
>> *I'm* the one that was dumb enough put them there in the first place! And I can't use "extensive Python experience" as an excuse ;)
>>
>
> It still leaves the question though, "Why isn't that working in D2? Bug or legitimate reason?".
>
> Jonathan suggested it was deliberate because of the hidden "this" parameter, but I'm not convinced because 1) D1 has the hidden "this" param too, but it handles it just fine, and 2) It's just a syntactical issue, so I don't see how semantics could be a problem unless there's some other change in D2 that causes a conflict or ambiguity with that feature.
>
> In any case, the error message seems to indicate that, deliberate or not, it's likely some sort of symbol-lookup/visibility issue.
>
>
It worked in 2.012 and earlier, but failed in 2.020. I don't have any intermediate versions installed.
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July 28, 2010 Re: Still unresolved (Was: D1->D2 member call syntax regression?) | ||||
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Posted in reply to Don | "Don" <nospam@nospam.com> wrote in message news:i2q0un$2hud$1@digitalmars.com... > Nick Sabalausky wrote: >> >> It still leaves the question though, "Why isn't that working in D2? Bug or legitimate reason?". >> >> Jonathan suggested it was deliberate because of the hidden "this" parameter, but I'm not convinced because 1) D1 has the hidden "this" param too, but it handles it just fine, and 2) It's just a syntactical issue, so I don't see how semantics could be a problem unless there's some other change in D2 that causes a conflict or ambiguity with that feature. >> >> In any case, the error message seems to indicate that, deliberate or not, it's likely some sort of symbol-lookup/visibility issue. >> >> > It worked in 2.012 and earlier, but failed in 2.020. I don't have any intermediate versions installed. I've gone ahead and filed a bug report: http://d.puremagic.com/issues/show_bug.cgi?id=4525 |
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