Hi all,

If I use zip() to collate together one or more ranges, the individual elements get returned as a Tuple of the corresponding types.

Is there any way to get zip to label those elements, i.e. to return e.g.

	Tuple!(int, "one", float, "two")

instead of

	Tuple!(int, float)

.... ?

Joseph Rushton Wakeling:

> If I use zip() to collate together one or more ranges, the individual elements
> get returned as a Tuple of the corresponding types.
>
> Is there any way to get zip to label those elements, i.e. to return e.g.

See:
http://d.puremagic.com/issues/show_bug.cgi?id=8715

I think currently you have to use map!() to replace the tuple. Maybe am unsafe map-cast suffices:

import std.stdio, std.range, std.algorithm, std.typecons;

void main() {
    auto r1 = zip(["red", "blue"], [10, 20]);
    r1.writeln;
    alias T2 = Tuple!(string,"col", int,"val");
    r1.map!(r => T2(r[])).writeln;
    r1.map!(r => cast(T2)r).writeln;
}

Bye,
bearophile

On 05/15/2013 08:00 PM, bearophile wrote:
> I think currently you have to use map!() to replace the tuple. Maybe am unsafe
> map-cast suffices:

Feels a bit nasty, and I have the feeling it would probably slow things down ... ? :-(

I like the zipWith idea, though I can't help but wish zip() itself was flexible enough to allow something like,

	zip(arr1, "one", arr2, "two")

... though I guess that would fall over if you ever wanted to use zip to lock together two immutable strings.