public string remove(string str, size_t start, size_t n) { }

I need something like this, similar to .Net, does Phobos have this?
I have looked at removechars in std.string and this is not suitable for me.
Do I need to roll my own?

Thank you.

On 01/29/2013 05:37 PM, Damian wrote:
> public string remove(string str, size_t start, size_t n) { }
>
> I need something like this, similar to .Net, does Phobos have this?
> I have looked at removechars in std.string and this is not suitable for me.
> Do I need to roll my own?

Yes but it's extremely simple with a huge warning sign on it: :)

import std.stdio;

void main()
{
    auto s = "neighbour";
    s = s[0..7] ~ s[8..$];
    assert(s == "neighbor");
}

The program is correct only if the string is a dchar string or it contains ASCII characters only.

The correct apprach is to treat strings as what they are: dchar ranges. Looks like removeAt() is pretty easy to implement when there is no error checking. :p

import std.stdio;
import std.range;

R removeAt(R)(R range, size_t i)
{
    auto rest = range.save;
    rest.popFrontN(i + 1);
    return range[0 .. i] ~ rest;
}

void main()
{
    auto s = "neighbour";
    assert(s.removeAt(7) == "neighbor");
}

Here is another one that uses the reduced range lazily:

import std.stdio;
import std.range;
import std.algorithm;

auto removeAt(R)(R range, size_t i)
{
    auto rest = range.save;
    rest.popFrontN(i + 1);
    return [range[0 .. i], rest].chain.joiner;
}

void main()
{
    auto s = "neighbour";
    assert(s.removeAt(7).array == "neighbor");
}

Ali

On 2013-01-30 04:27, Ali Çehreli wrote:
>      s = s[0..7] ~ s[8..$];

As with the other slicing approaches, it would be best to check first if s.length >= i (with i = 8 in this case).