This:	
        double b = 1.0;

	Variant[string] aa = ["b": &b];

	writeln(aa["b"]);

fails with:

Error: cannot implicitly convert expression(["b":&b]) of type double*[string] to VariantN!20u[string]

Helps please!

On Tuesday, 9 February 2016 at 03:49:11 UTC, Enjoys Math wrote:
> This:	
>         double b = 1.0;
>
> 	Variant[string] aa = ["b": &b];
>
> 	writeln(aa["b"]);
>
> fails with:
>
> Error: cannot implicitly convert expression(["b":&b]) of type double*[string] to VariantN!20u[string]
>
> Helps please!

Use an intermediate to carry the result of &<stuff>:

double b = 1.0;
Variant vb = &b;
Variant[string] aa = ["b": vb];
writeln(aa["b"]);

&b is a rvalue.
vb is a lvalue.

On 02/08/2016 07:49 PM, Enjoys Math wrote:
> This:
>          double b = 1.0;
>
>      Variant[string] aa = ["b": &b];
>
>      writeln(aa["b"]);
>
> fails with:
>
> Error: cannot implicitly convert expression(["b":&b]) of type
> double*[string] to VariantN!20u[string]
>
> Helps please!

When initializing the array, you have to use Variant(&b):

import std.stdio;
import std.variant;

void main() {
    double b = 1.5;

    Variant[string] aa = ["b": Variant(&b)];

    writeln(aa);
    writeln(aa["b"]);
    writeln(*aa["b"].get!(double*));
}

Prints something like the following:

["b":7FFD0104B100]
7FFD0104B100
1.5

Ali

On Tuesday, 9 February 2016 at 03:49:11 UTC, Enjoys Math wrote:
> This:	
>         double b = 1.0;
>
> 	Variant[string] aa = ["b": &b];
>
> 	writeln(aa["b"]);
>
> fails with:
>
> Error: cannot implicitly convert expression(["b":&b]) of type double*[string] to VariantN!20u[string]
>
> Helps please!

I've found bugbears like this are distressingly common in std.variant.  Another one you might find yourself dealing with is https://issues.dlang.org/show_bug.cgi?id=10223, which applies to AAs as much as regular arrays.  It's actually why I stopped using it in favour of Adam Ruppe's arsd.jsvar.

-Wyatt