struct Foo
{
   void stuff() { }
}
typedef Foo Bar;
int main()
{
   Bar b;
   b.stuff(); // here
   return 0;
}


DMD 0.137 output:
   test.d(9): this for stuff needs to be type Foo not type Bar


Was this intended? If so, what is the reason? Shouldn't the type implicitly convert to its base to find the member?

On Fri, 28 Oct 2005 02:31:25 -0400, Vathix wrote:

> struct Foo
> {
>     void stuff() { }
> }
> typedef Foo Bar;
> int main()
> {
>     Bar b;
>     b.stuff(); // here
>     return 0;
> }
> 
> DMD 0.137 output:
>     test.d(9): this for stuff needs to be type Foo not type Bar
> 
> Was this intended? If so, what is the reason? Shouldn't the type implicitly convert to its base to find the member?

I must admit that this looks odd ...

struct Foo
{
    void stuff() { }
}
typedef Foo Bar;
int main()
{
    Bar b;
    (cast(Foo)b).stuff(); // now it works.
    return 0;
}


Also, instead of typedef, alias makes it compile, but I guess that's not your point.

-- 
Derek
(skype: derek.j.parnell)
Melbourne, Australia
28/10/2005 4:51:21 PM