In a post a while back ...

Walter wrote:

> "Trevor Parscal" <trevorparscal@hotmail.com> wrote in message
> news:d7hq0e$1qgp$1@digitaldaemon.com...
>
>> char[] word = "test";
>> char letter = '1';
>>
>> // Wont work?
>> word ~ letter;
>
>
>
> Right, but that's a compiler bug. It'll be fixed in the next update.
>

Ok. So in the next update, whenever you use

char[] array = "some";

array ~ "thing";

writefln(array); <-- will print "something"?

I thought you used ~= if you want to add append, and ~ if you just want it to return the appened value. I'm thoroughly confused.

On Sun, 05 Jun 2005 20:27:49 -0400, clayasaurus wrote:

> In a post a while back ...
> 
> Walter wrote:
> 
>  > "Trevor Parscal" <trevorparscal@hotmail.com> wrote in message
>  > news:d7hq0e$1qgp$1@digitaldaemon.com...
>  >
>  >> char[] word = "test";
>  >> char letter = '1';
>  >>
>  >> // Wont work?
>  >> word ~ letter;
>  >
>  >
>  >
>  > Right, but that's a compiler bug. It'll be fixed in the next update.
>  >
> 
> Ok. So in the next update, whenever you use
> 
> char[] array = "some";
> 
> array ~ "thing";
> 
> writefln(array); <-- will print "something"?
> 
> I thought you used ~= if you want to add append, and ~ if you just want it to return the appened value. I'm thoroughly confused.

I think that Walter was hinting that the concatenate operator will be working on the right hand side of an expression if one (or both?) of the types are the element types.

for eaxample:

   char[] a;
   char[] b;
   char c;

   a = b ~ c;

   if ( (c ~ a) == testval)
     . . .

Currently, you get the message "array cat with element not implemented" when you try these sort of things. I expect that the next release will implement this obvious usage.

-- 
Derek
Melbourne, Australia
6/06/2005 11:53:49 AM