Is there union literals?

I have this (example):

struct A
{
	int x;
}

struct B
{
	char z;
}

struct C
{
	int y;
	union U
	{
		A a;
		static struct D
		{
			B b;
			uint domain;
		}
		D d;
	}
	U u;
}

Is there any way to initialize a C in one line (so it can be const)? Like:

const c = C(10, C.U.D(B('b'), 15));

But I get: Error: cannot implicitly convert expression (D((B('b')),15u))
           of type D to A.

Unions can only be initalized to its first member?



-- 
Leandro Lucarella (luca) | Blog colectivo: http://www.mazziblog.com.ar/blog/
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"Leandro Lucarella" <llucax@gmail.com> wrote in message news:20080207212438.GB16062@burns.springfield.home...

> Is there any way to initialize a C in one line (so it can be const)? Like:
>
> const c = C(10, C.U.D(B('b'), 15));

Since it's const, you can use the oh-so-special struct initializer syntax:

const C c = { y: 10, u: { d: { b: B('b'), domain: 15}}};

But this is getting a little ugly.

I'm not sure if the struct you posted was stripped down from a larger struct, or if you're just unaware of the fact that D has anonymous structs and unions.  C can be declared more simply as:

struct C
{
    int y;

    union
    {
        A a;

        struct
        {
            B b;
            uint domain;
        }
    }
}

And then initialized:

const C c = { y: 10, b: B('b'), domain: 15 };

Also any instances of C you create, you no longer have to write "c.u.d.b" etc., just "c.b".