The following code snippit generated this error:
err.d(9): Foo is used as a type

struct Foo(T)
{
	T x = 0;

	static Foo bar(T c1)
	{
		Foo rtn; // Error here
		rtn.x = c1;
		return rtn;
	}
}

void func()
{
  alias Foo!(double) vector;

  vector xAxis = vector.bar(1);
}

struct Foo(T)
{
 T x = 0;

 static Foo bar(T c1)
 {
  Foo !(double) rtn; // must instantiate with type
  rtn.x = c1;
  return rtn;
 }
}

void func()
{
  alias Foo!(double) vector;
  vector xAxis = vector.bar(1);
}

Howerver if use T to instatiate Foo , I get

identifier 'T' is not defined

Changing the code to
==============

struct Foo(T)
{
 T x = 0;

 static Foo bar(T c1)
 {
  Foo !(typeof(c1) ) rtn; // must instantiate with type
  rtn.x = c1;
  return rtn;
 }
}

void func()
{
  alias Foo!(double) vector;
  vector xAxis = vector.bar(1);
}

void main () { func(); }

Works and is probably what you want ?

C



C

void main () { func(); }
"Patrick Down" <pat@codemoon.com> wrote in message
news:Xns9470D8C2F1A87patcodemooncom@63.105.9.61...
>
> The following code snippit generated this error:
> err.d(9): Foo is used as a type
>
> struct Foo(T)
> {
> T x = 0;
>
> static Foo bar(T c1)
> {
> Foo rtn; // Error here
> rtn.x = c1;
> return rtn;
> }
> }
>
> void func()
> {
>   alias Foo!(double) vector;
>
>   vector xAxis = vector.bar(1);
> }

Chaing bar to be a non-static method T is still an undefined identifier , why is that ?

C
"C" <dont@respond.com> wrote in message
news:bu51u2$boo$1@digitaldaemon.com...
> struct Foo(T)
> {
>  T x = 0;
>
>  static Foo bar(T c1)
>  {
>   Foo !(double) rtn; // must instantiate with type
>   rtn.x = c1;
>   return rtn;
>  }
> }
>
> void func()
> {
>   alias Foo!(double) vector;
>   vector xAxis = vector.bar(1);
> }
>
> Howerver if use T to instatiate Foo , I get
>
> identifier 'T' is not defined
>
> Changing the code to
> ==============
>
> struct Foo(T)
> {
>  T x = 0;
>
>  static Foo bar(T c1)
>  {
>   Foo !(typeof(c1) ) rtn; // must instantiate with type
>   rtn.x = c1;
>   return rtn;
>  }
> }
>
> void func()
> {
>   alias Foo!(double) vector;
>   vector xAxis = vector.bar(1);
> }
>
> void main () { func(); }
>
> Works and is probably what you want ?
>
> C
>
>
>
> C
>
> void main () { func(); }
> "Patrick Down" <pat@codemoon.com> wrote in message
> news:Xns9470D8C2F1A87patcodemooncom@63.105.9.61...
> >
> > The following code snippit generated this error:
> > err.d(9): Foo is used as a type
> >
> > struct Foo(T)
> > {
> > T x = 0;
> >
> > static Foo bar(T c1)
> > {
> > Foo rtn; // Error here
> > rtn.x = c1;
> > return rtn;
> > }
> > }
> >
> > void func()
> > {
> >   alias Foo!(double) vector;
> >
> >   vector xAxis = vector.bar(1);
> > }
>
>

inline

"C" <dont@respond.com> wrote in news:bu51u2$boo$1@digitaldaemon.com:

> struct Foo(T)
> {
>  T x = 0;
> 
>  static Foo bar(T c1)
>  {
>   Foo !(double) rtn; // must instantiate with type
>   rtn.x = c1;
>   return rtn;
>  }
> }
> 
> void func()
> {
>   alias Foo!(double) vector;
>   vector xAxis = vector.bar(1);
> }
> 
> Howerver if use T to instatiate Foo , I get
> 
> identifier 'T' is not defined

Yeah I had the same problem.

Foo!(T) rtn; should work.  I think this is the
real bug.

> 
> Changing the code to
> ==============
> 
> struct Foo(T)
> {
>  T x = 0;
> 
>  static Foo bar(T c1)
>  {
>   Foo !(typeof(c1) ) rtn; // must instantiate with type
>   rtn.x = c1;
>   return rtn;
>  }
> }
> 
> void func()
> {
>   alias Foo!(double) vector;
>   vector xAxis = vector.bar(1);
> }
> 
> void main () { func(); }
> 
> Works and is probably what you want ?
> 
> C

Yes that works,

Thanks.


> 
> 
> 
> C
> 
> void main () { func(); }
> "Patrick Down" <pat@codemoon.com> wrote in message
> news:Xns9470D8C2F1A87patcodemooncom@63.105.9.61...
>>
>> The following code snippit generated this error:
>> err.d(9): Foo is used as a type
>>
>> struct Foo(T)
>> {
>> T x = 0;
>>
>> static Foo bar(T c1)
>> {
>> Foo rtn; // Error here
>> rtn.x = c1;
>> return rtn;
>> }
>> }
>>
>> void func()
>> {
>>   alias Foo!(double) vector;
>>
>>   vector xAxis = vector.bar(1);
>> }
> 
> 

This give me the error:
template instance Foo!(double) Foo is not a template declaration


struct Foo(T)
{
  T x = 0;

  static Foo!(T) bar(T c1)
  {
    Foo!(typeof(c1)) rtn;
    rtn.x = c1;
    return rtn;
  }
}

void func()
{
  alias Foo!(double) vector;

  vector xAxis = vector.bar(1);
}

void main () { func(); }


"C" <dont@respond.com> wrote in news:bu51u2$boo$1@digitaldaemon.com:

> struct Foo(T)
> {
>  T x = 0;
> 
>  static Foo bar(T c1)
>  {
>   Foo !(double) rtn; // must instantiate with type
>   rtn.x = c1;
>   return rtn;
>  }
> }
> 
> void func()
> {
>   alias Foo!(double) vector;
>   vector xAxis = vector.bar(1);
> }
> 
> Howerver if use T to instatiate Foo , I get
> 
> identifier 'T' is not defined
> 
> Changing the code to
> ==============
> 
> struct Foo(T)
> {
>  T x = 0;
> 
>  static Foo bar(T c1)
>  {
>   Foo !(typeof(c1) ) rtn; // must instantiate with type
>   rtn.x = c1;
>   return rtn;
>  }
> }
> 
> void func()
> {
>   alias Foo!(double) vector;
>   vector xAxis = vector.bar(1);
> }
> 
> void main () { func(); }
> 
> Works and is probably what you want ?
> 
> C
> 
> 
> 
> C
> 
> void main () { func(); }
> "Patrick Down" <pat@codemoon.com> wrote in message
> news:Xns9470D8C2F1A87patcodemooncom@63.105.9.61...
>>
>> The following code snippit generated this error:
>> err.d(9): Foo is used as a type
>>
>> struct Foo(T)
>> {
>> T x = 0;
>>
>> static Foo bar(T c1)
>> {
>> Foo rtn; // Error here
>> rtn.x = c1;
>> return rtn;
>> }
>> }
>>
>> void func()
>> {
>>   alias Foo!(double) vector;
>>
>>   vector xAxis = vector.bar(1);
>> }
> 
>