Do you know what's causing the difference in the outouts?

void main() {
  double d1 = 3.14159;
  printf("%a\n", d1);
  writefln("%a\n", d1);
}

Outputs:
0x1.921f9f01b866ep+1
0xc.90fcf80dc337p-2

A printf in C code compiled with GCC prints the same as the printf here.

Bye,
bearophile

Hello bearophile,

> Do you know what's causing the difference in the outouts?
> 
> void main() {
> double d1 = 3.14159;
> printf("%a\n", d1);
> writefln("%a\n", d1);
> }
> Outputs:
> 0x1.921f9f01b866ep+1
> 0xc.90fcf80dc337p-2
> A printf in C code compiled with GCC prints the same as the printf
> here.
> 
> Bye,
> bearophile

Just a guess: D is correctly using double and C is assuming float? Try running it with d1 as a float to check.

BCS:
> Just a guess: D is correctly using double and C is assuming float? Try running it with d1 as a float to check.

I have run the code again with the last D1 compiler, and now writeln is giving the same result as printf. So probably it was a writefln bug that's already fixed.
Sorry for the useless noise -.-

Bye,
bearophile