Hi. I'm 100% new in D, but I know C/C++. I've been reviewing the help and the forum, and there's something that I still can't find: how can I read strings (or an array of chars) from the keyboard. I know it sounds silly, but believe me, I can't. Also, this code doesn't work:

import c.stdio;

void main()
{
float f;

scanf("%f",&f);
printf("You entered: %f\n",f);
}

It shows "You entered: 0.0000", doesn't matter what you enter. It works if f is int or char, but not if float. Why? Is it that there're some easter-eggs in D?

Thanks

"Carlos" <Carlos_member@pathlink.com> wrote in message news:aapkrj$24b0$1@digitaldaemon.com...
> Hi. I'm 100% new in D, but I know C/C++. I've been reviewing the help and
the
> forum, and there's something that I still can't find: how can I read
strings (or
> an array of chars) from the keyboard.

At the moment, use the corresponding C functions.

> I know it sounds silly, but believe me, I
> can't. Also, this code doesn't work:
>
> import c.stdio;
>
> void main()
> {
> float f;
>
> scanf("%f",&f);
> printf("You entered: %f\n",f);
> }
>
> It shows "You entered: 0.0000", doesn't matter what you enter. It works if
f is
> int or char, but not if float. Why? Is it that there're some easter-eggs
in D?

What's happening is that, unlike C, the f is passed to printf() as a float. It is interpreted by printf, however, as a double. You can fix it with:

    printf("You entered: %f\n", (double)f);

How am I supposed to do the string reading? I've tried everything. This should be the way, but doesn't work:

import c.stdio;

void main()
{
char[] str;
scanf("%s",str); //or should I use gets()? or &str?
printf("You wrote: %.*s\n",str);
}

---------

In article <aapnca$2958$1@digitaldaemon.com>, Walter says...
>
>
>"Carlos" <Carlos_member@pathlink.com> wrote in message news:aapkrj$24b0$1@digitaldaemon.com...
>> Hi. I'm 100% new in D, but I know C/C++. I've been reviewing the help and
>the
>> forum, and there's something that I still can't find: how can I read
>strings (or
>> an array of chars) from the keyboard.
>
>At the moment, use the corresponding C functions.
>
>> I know it sounds silly, but believe me, I
>> can't. Also, this code doesn't work:
>>
>> import c.stdio;
>>
>> void main()
>> {
>> float f;
>>
>> scanf("%f",&f);
>> printf("You entered: %f\n",f);
>> }
>>
>> It shows "You entered: 0.0000", doesn't matter what you enter. It works if
>f is
>> int or char, but not if float. Why? Is it that there're some easter-eggs
>in D?
>
>What's happening is that, unlike C, the f is passed to printf() as a float. It is interpreted by printf, however, as a double. You can fix it with:
>
>    printf("You entered: %f\n", (double)f);
>
>
>

"Carlos" <Carlos_member@pathlink.com> wrote in message news:aaq2ep$15l$1@digitaldaemon.com...
> How am I supposed to do the string reading? I've tried everything. This
should
> be the way, but doesn't work:
>
> import c.stdio;
>
> void main()
> {
> char[] str;
> scanf("%s",str); //or should I use gets()? or &str?
> printf("You wrote: %.*s\n",str);
> }

The key is C doesn't do dynamic arrays, it does pointers. So:

    char[] str;
    char *s;
    scanf("%s", &s);
    str = s[0 .. c.strlen(s)];

Walter wrote:
> "Carlos" <Carlos_member@pathlink.com> wrote in message
> news:aaq2ep$15l$1@digitaldaemon.com...
> 
>>How am I supposed to do the string reading? I've tried everything. This
> 
> should
> 
>>be the way, but doesn't work:
>>
>>import c.stdio;
>>
>>void main()
>>{
>>char[] str;
>>scanf("%s",str); //or should I use gets()? or &str?
>>printf("You wrote: %.*s\n",str);
>>}
> 
> 
> The key is C doesn't do dynamic arrays, it does pointers. So:
> 
>     char[] str;
>     char *s;
>     scanf("%s", &s);
>     str = s[0 .. c.strlen(s)];
> 
> 

Ack, that 'taint right, is it? s is uninitialized there,
and the scanf is getting a pointer to pointer!

(Although, I have a whole closet full of ten foot poles
with which I wouldn't touch scanf() in the first place...)

-R

"Russell Borogove" <kaleja@estarcion.com> wrote in message news:3CD21E39.7020500@estarcion.com...
> >     char[] str;
> >     char *s;
> >     scanf("%s", &s);
> >     str = s[0 .. c.strlen(s)];
> Ack, that 'taint right, is it? s is uninitialized there, and the scanf is getting a pointer to pointer!

scanf initializes the pointer.

> (Although, I have a whole closet full of ten foot poles
> with which I wouldn't touch scanf() in the first place...)

I usually find myself writing a real lexer when I need one <g>.

Walter wrote:
> "Russell Borogove" <kaleja@estarcion.com> wrote in message
> news:3CD21E39.7020500@estarcion.com...
> 
>>>    char[] str;
>>>    char *s;
>>>    scanf("%s", &s);
>>>    str = s[0 .. c.strlen(s)];
>>
>>Ack, that 'taint right, is it? s is uninitialized there,
>>and the scanf is getting a pointer to pointer!
> 
> 
> scanf initializes the pointer.

Not in standard C:
# s  Matches a sequence of non-white-space characters.
#    The corresponding argument shall be a pointer to
#    the initial character of an array large enough to
#    accept the sequence and a terminating null
#    character...

(Unless that's a D scanf and I'm missing something?)

I think you want:

char s[ DO_YOU_FEEL_LUCKY_LENGTH ];
scanf( "%s", s );

-R

Oops! You're right. Yet another reason to use D!

"Russell Borogove" <kaleja@estarcion.com> wrote in message news:3CD2BE38.4000802@estarcion.com...
> Walter wrote:
> > "Russell Borogove" <kaleja@estarcion.com> wrote in message news:3CD21E39.7020500@estarcion.com...
> >
> >>>    char[] str;
> >>>    char *s;
> >>>    scanf("%s", &s);
> >>>    str = s[0 .. c.strlen(s)];
> >>
> >>Ack, that 'taint right, is it? s is uninitialized there, and the scanf is getting a pointer to pointer!
> >
> >
> > scanf initializes the pointer.
>
> Not in standard C:
> # s  Matches a sequence of non-white-space characters.
> #    The corresponding argument shall be a pointer to
> #    the initial character of an array large enough to
> #    accept the sequence and a terminating null
> #    character...
>
> (Unless that's a D scanf and I'm missing something?)
>
> I think you want:
>
> char s[ DO_YOU_FEEL_LUCKY_LENGTH ];
> scanf( "%s", s );
>
> -R
>

Walter wrote:
> Oops! You're right. Yet another reason to use D!
> 

lol... IMO, scanf() is a fine reason to use COBOL
or BASIC!

-R

>
> The key is C doesn't do dynamic arrays, it does pointers. So:
>
>     char[] str;
>     char *s;
>     scanf("%s", &s);
>     str = s[0 .. c.strlen(s)];
>
>

Like this?

import c.stdio;
import string;

void main()
{
    char[] w;
    char *w1;

    printf("Write your name: ");
    scanf("%s",&w);
    w=w1[0..strlen(w1)];
    printf("Hi, %.*s\n",w);
}

Doesn't work!