I have been scratching my head trying to figure this out.  How to declare a dynamic array of dynamic strings and access then strings.  I have tried the following:

char[]*[] stringArray;
// read from file into char[] tempHolder.  It reads in thew string alright as I have succesfully displayed iot
// back to the screen.  This step could probably be done away with and read staright into the string array.

// then copy into string Array
stringArray[stringArray.length - 1] = new char[tempHolder.length];

//or
char[][] stringArray;
stringArray[stringArray.length - 1] = tempHolder;

Both produce errors.
I have been working on this code for hours.  I would like the strings to be dynamic by the way so I'm not sure
whether method 1 is the best way to go.

ryan

"Ryan Michel" <ryan@michel.com.au> wrote in message news:1103_1023449782@news.digitalmars.com...

> I have been scratching my head trying to figure this out.  How to declare
a dynamic array of dynamic strings and

char[][] stringlist;

stringlist ~= "foo";
stringlist ~= "bar";
stringlist ~= "baz";

for (int i = 0; i < stringlist.length; i++)
    printf("%.*s\n", stringlist[i]);

char[][] stringArray;
makes an empty array of strings. So stringArray.length-1 = -1. Accessing
stringArray[-1] produces a compile-time error.

I also have a problem with strings. What's bad in this?

import c.stdio;
int main()
{
    char*[3] lines =
    [   "Per me si va nella citta' dolente,",
        "Per me si va nell'etterno dolore,",
        "Per me si va tra la perduta gente."
    ];
    blah(lines);
    return 0;
}
void blah(char*[] lines)
{
    for(int i; i < lines.length; ++i) printf('%s' \n, lines[i]);
}

The compiler says:
Assertion failure: 'ie' on line 253 in file 'declaration.c'
abnormal program termination

Is this a compiler bug?

Move the initialized array out of the function.

Sean

"Dario" <supdar@yahoo.com> wrote in message news:adt6mj$lbq$1@digitaldaemon.com...
> char[][] stringArray;
> makes an empty array of strings. So stringArray.length-1 = -1. Accessing
> stringArray[-1] produces a compile-time error.
>
> I also have a problem with strings. What's bad in this?
>
> import c.stdio;
> int main()
> {
>     char*[3] lines =
>     [   "Per me si va nella citta' dolente,",
>         "Per me si va nell'etterno dolore,",
>         "Per me si va tra la perduta gente."
>     ];
>     blah(lines);
>     return 0;
> }
> void blah(char*[] lines)
> {
>     for(int i; i < lines.length; ++i) printf('%s' \n, lines[i]);
> }
>
> The compiler says:
> Assertion failure: 'ie' on line 253 in file 'declaration.c'
> abnormal program termination
>
> Is this a compiler bug?
>
>

Incredible, that's works. Maybe I'll seem stupid, but why can't I write it
in the function?
Moreover, can I write this?:
    blah( ["one", "two", "three"] );

"Sean L. Palmer" wrote
> Move the initialized array out of the function.
>
> Sean

"Dario" <supdar@yahoo.com> wrote in message news:adtlvs$14li$1@digitaldaemon.com...
> Incredible, that's works. Maybe I'll seem stupid, but why can't I write it in the function?

You can, it just needs to be 'static'. It's a bug in the compiler.

> Moreover, can I write this?:
>     blah( ["one", "two", "three"] );

Not yet <g>.

> > Incredible, that's works. Maybe I'll seem stupid, but why can't I write
it
> > in the function?
> You can, it just needs to be 'static'. It's a bug in the compiler.

> > Moreover, can I write this?:
> >     blah( ["one", "two", "three"] );
> Not yet <g>.

So it is going to be supported, is it in the specs? Where can I found info about it?

"Dario" <supdar@yahoo.com> wrote in message news:aekb6u$1huf$1@digitaldaemon.com...
> > > Incredible, that's works. Maybe I'll seem stupid, but why can't I
write
> it
> > > in the function?
> > You can, it just needs to be 'static'. It's a bug in the compiler.
>
> > > Moreover, can I write this?:
> > >     blah( ["one", "two", "three"] );
> > Not yet <g>.
>
> So it is going to be supported, is it in the specs? Where can I found info about it?

It'll get supported, but it isn't in the specs yet. -Walter