Hello Everybody

I have broken my wrist so I will keep this sort.. is there any way overload were the return is the unique section.. Just an example:

function long  add(int, int)
function int   add(int, int)

main() {
        long a;
        int b;
        a = add(1,1) // this would use the first add
        b = add(1,1) // this would use the second add
}

Thanks Ben

Short answer is NO.

D does not support overloading. You'd have to do something like

long  addl(int, int)
int   addi(int, int)

I've been tring to convice Walter to consider explicit overloading using the cast idea Pavel came up with.

//For return types
float abs(float n) {} //Default
int cast(int, long) abs(float n) {}
int cast(double) abs(float n) {}

//For parameters
float abs(float n) {} //Default
float abs(float cast(int, long) n) {}
float abs(float cast(double) n) {}


"ben" <zander@echotech.ca> wrote in message news:afcb1q$158i$1@digitaldaemon.com...
> Hello Everybody
>
> I have broken my wrist so I will keep this sort.. is there any way
overload
> were the return is the unique section.. Just an example:
>
> function long  add(int, int)
> function int   add(int, int)
>
> main() {
>         long a;
>         int b;
>         a = add(1,1) // this would use the first add
>         b = add(1,1) // this would use the second add
> }
>
> Thanks Ben

"anderson" <anderson@firestar.com.au> wrote in message news:afcgkn$1etm$1@digitaldaemon.com...
> Short answer is NO.
>
D does not support return overloading. You'd have to do something like

 long  addl(int, int)
int   addi(int, int)

> I've been tring to convice Walter to consider explicit overloading using
the
> cast idea Pavel came up with.
>
> //For return types
> float abs(float n) {} //Default
> int cast(int, long) abs(float n) {}
> int cast(double) abs(float n) {}
>
> //For parameters
> float abs(float n) {} //Default
> float abs(float cast(int, long) n) {}
> float abs(float cast(double) n) {}
>
>
> "ben" <zander@echotech.ca> wrote in message news:afcb1q$158i$1@digitaldaemon.com...
> > Hello Everybody
> >
> > I have broken my wrist so I will keep this sort.. is there any way
> overload
> > were the return is the unique section.. Just an example:
> >
> > function long  add(int, int)
> > function int   add(int, int)
> >
> > main() {
> >         long a;
> >         int b;
> >         a = add(1,1) // this would use the first add
> >         b = add(1,1) // this would use the second add
> > }
> >
> > Thanks Ben
>
>

Ok thanks. I guess that would lead to alot of problem code, but it could be usefull for math programming, I wish I had an example off hand but I don't, as i have been working on a few porjects i have noticed that I could not do that with c++ and it would have helped me in a few occations.

Thanks Ben

anderson wrote:

> 
> "anderson" <anderson@firestar.com.au> wrote in message news:afcgkn$1etm$1@digitaldaemon.com...
>> Short answer is NO.
>>
> D does not support return overloading. You'd have to do something like
> 
>  long  addl(int, int)
> int   addi(int, int)
> 
>> I've been tring to convice Walter to consider explicit overloading using
> the
>> cast idea Pavel came up with.
>>
>> //For return types
>> float abs(float n) {} //Default
>> int cast(int, long) abs(float n) {}
>> int cast(double) abs(float n) {}
>>
>> //For parameters
>> float abs(float n) {} //Default
>> float abs(float cast(int, long) n) {}
>> float abs(float cast(double) n) {}
>>
>>
>> "ben" <zander@echotech.ca> wrote in message news:afcb1q$158i$1@digitaldaemon.com...
>> > Hello Everybody
>> >
>> > I have broken my wrist so I will keep this sort.. is there any way
>> overload
>> > were the return is the unique section.. Just an example:
>> >
>> > function long  add(int, int)
>> > function int   add(int, int)
>> >
>> > main() {
>> >         long a;
>> >         int b;
>> >         a = add(1,1) // this would use the first add
>> >         b = add(1,1) // this would use the second add
>> > }
>> >
>> > Thanks Ben
>>
>>