> This is a very common mistake.  D strings are
> not null terminated, except for the constant
> ones defined inline.  Try this instead.
>
> printf("%.*s\n",two);
>
>

Is that a period and an asterisk following the percent sign? Or is it just an asterisk?

A period and an asterisk.


"John Reimer" <jjreimer@telus.net> wrote in message news:b58hah$1mjl$1@digitaldaemon.com...
> > This is a very common mistake.  D strings are
> > not null terminated, except for the constant
> > ones defined inline.  Try this instead.
> >
> > printf("%.*s\n",two);
> >
> >
>
> Is that a period and an asterisk following the percent sign? Or is it just an asterisk?
>
>
>

You need to use the "%.*s" syntax to use only the contents of the slice. "%s" uses a char * - which you've cast it to - and since the slice is a copy-on-write view into the original array, you get the rest of the original because a null-terminator is not contained in the slice.

If you want a slice that you can treat as a ZTS, you need to append the null terminator with

  two ~= (char)0;

(although I may be wrong - it's been a while)


"Steve Adams" <adamss@ascinet.com> wrote in message news:b58ekm$1kqe$1@digitaldaemon.com...
> Can someone clear this up for me?  The following code doesn't work the way that I would expect from the description of slices.
>
>
> int main()
> {
>   char[] one = "abc\ndef\n";
>   char[] two = one[0..3];
>   printf( "%s\n", cast(char *) one );
>   return( 0 );
> }
>
> generates as output
>
>   abc
>   def
>
> instead of just
>   abc
>
>
>

Steve Adams wrote:

> Seems like it's a pointer and a count (since strings are counted).  Not a
> bad model, until
> you want to print it out.  I'm working around it with
>
>   printf( "%.*s\n", two.length, (char *)two );

> but that seems rather wasteful.  Either the cast should really do a case, or
> there should be
> a format specifier for the counted strings.
>
> Might be a way to do this with an array copy too I suppose.

This works, but not on Linux.  The solution I use (which has a performance hit,
unfortunately) is:

    printf("%s\n", (char*)(two~\0));

Appending to the array causes a copy to be made, so this doesn't overwrite 'one'.

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