Hi,

how can i cast from char[] to byte?

import outbuffer;

int main () {
        //byte by = 0x4d;
        byte  by;
        OutBuffer buf = new OutBuffer();
        char [] del=' ',hex_string ='0x4d 0x42';
        char [][] str;

        str = split(hex_string,del);
        printf("%.*s\n",str[0]);
        by = cast(byte) str[0];
        buf.write(cast(byte)by); // Here is the problem
        printf("buf = '%.*s'\n", buf.toString());
        return 0;
}

By the way, the linux port from dmd works nice.


Regards Manfred

Manfred Hansen wrote:
> Hi,
> 
> how can i cast from char[] to byte?

I don't understand what kind of conversion result you expect.

> import outbuffer;
> 
> int main () {
>         //byte by = 0x4d;
>         byte  by;
>         OutBuffer buf = new OutBuffer();
>         char [] del=' ',hex_string ='0x4d 0x42';
>         char [][] str;

So "str" is an array of strings.

> 
>         str = split(hex_string,del);
>         printf("%.*s\n",str[0]);
>         by = cast(byte) str[0];

you're converting an *array* (a string) into a *value* - which makes no sense.

Have you meant:

         by = cast(byte) (str[0][0]);

>         buf.write(cast(byte)by); // Here is the problem

why here? "by" is a byte, casting it to byte is redundant.

>         printf("buf = '%.*s'\n", buf.toString());
>         return 0;
> }

Thus modified proggie gives following output:

0x4d
buf = '0'

-i.

Ilya Minkov wrote:

> Manfred Hansen wrote:
>> Hi,
>> 
>> how can i cast from char[] to byte?
> 
> I don't understand what kind of conversion result you expect.

I want the output 'M' .
4d is the ASCII code for M.
In my real programm i will sent hex number's to the socket
for communication to the mysql server (linux), but i believe this
is a long way.

> 
>> import outbuffer;
>> 
>> int main () {
>>         //byte by = 0x4d;
>>         byte  by;
>>         OutBuffer buf = new OutBuffer();
>>         char [] del=' ',hex_string ='0x4d 0x42';
>>         char [][] str;
> 
> So "str" is an array of strings.
> 
>> 
>>         str = split(hex_string,del);
>>         printf("%.*s\n",str[0]);
>>         by = cast(byte) str[0];
> 
> you're converting an *array* (a string) into a *value* - which makes no
> sense.
> 
> Have you meant:
> 
>           by = cast(byte) (str[0][0]);
> 
>>         buf.write(cast(byte)by); // Here is the problem
> 
> why here? "by" is a byte, casting it to byte is redundant.

Oh, yes this was wrong from me. I mean'd this line " by = cast(byte) str[0];"

> 
>>         printf("buf = '%.*s'\n", buf.toString());
>>         return 0;
>> }
> 
> Thus modified proggie gives following output:
> 
> 0x4d
> buf = '0'
That's not what i want. I will get buf = 'M' .

> 
> -i.

Regards Manfred

Manfred Hansen wrote:
> I want the output 'M' .
> 4d is the ASCII code for M.
> In my real programm i will sent hex number's to the socket for communication to the mysql server (linux), but i believe this is a long way.

Hmm... hex numbers? Well, as you wish. I know nothing about MySQL.

> Oh, yes this was wrong from me. I mean'd this line " by = cast(byte) str[0];"  

str is an *array* of *strings*. It is like you have a sheet of lined paper, on which you must first select a line, then a column. That is, you want to take one character like:

	by = str[line][column];	 //add a cast if it complains

str[x] would give you the whole line of charcters. Also think whether a string would be more appropriate ("char [] str;") - i'm still unclear about what you want and how you intend it to work, bit the name "str" suggests it being a string, not an array of strings.

Then, if you want to print a byte as a character, why don't you cast it into a character? Consider: "buf.write" resolves to different functions depending on a formal data type.

-i.