Why doesn't this code work? I'm using dmd 0.69. It worked with 0.68..

void main()
{
 char[] s = "Hello";
 if(s[0] == "H")
 {
  printf(s);
 }
}

I get:

hello.d(4): incompatible types for ((cast(int)(s[0])) == ("H")): 'int' and
'char[1]'

"H" is a char[1]  s[0] is a char
try 'H' (char literal, not string literal) or "H"[0] !
there has been a change \n is not '\n' and 'foo' is not a string anymore.

"Mårten Ask" <majbritt37@hotmail.com> wrote in message news:bhm5nk$7jf$1@digitaldaemon.com...
> Why doesn't this code work? I'm using dmd 0.69. It worked with 0.68..
>
> void main()
> {
>  char[] s = "Hello";
>  if(s[0] == "H")
>  {
>   printf(s);
>  }
> }
>
> I get:
>
> hello.d(4): incompatible types for ((cast(int)(s[0])) == ("H")): 'int' and
> 'char[1]'
>
>

Thanks, it worked right away with single quotes. I feel stupid. :)

"Mike Wynn" <mike.wynn@l8night.co.uk> skrev i meddelandet news:bhm8d5$bgh$1@digitaldaemon.com...
> "H" is a char[1]  s[0] is a char
> try 'H' (char literal, not string literal) or "H"[0] !
> there has been a change \n is not '\n' and 'foo' is not a string anymore.
>
> "Mårten Ask" <majbritt37@hotmail.com> wrote in message news:bhm5nk$7jf$1@digitaldaemon.com...
> > Why doesn't this code work? I'm using dmd 0.69. It worked with 0.68..
> >
> > void main()
> > {
> >  char[] s = "Hello";
> >  if(s[0] == "H")
> >  {
> >   printf(s);
> >  }
> > }
> >
> > I get:
> >
> > hello.d(4): incompatible types for ((cast(int)(s[0])) == ("H")): 'int'
and
> > 'char[1]'
> >
> >
>
>

> Thanks, it worked right away with single quotes. I feel stupid. :)

Don't feel stupid. Feel her smarter older sister!

(Sorry, am a bit low on blood sugar at the moment ...)

> (Sorry, am a bit low on blood sugar at the moment ...)
> 

Well! You know how to fix that! LOL