This code:

void main() {
 struct A { char c='c'; int i=5; float f=3.14; }
 enum B { X, Y, Z }
 static A [B] a;
 a[B.X].c='x';
 a[B.Y].i=-1;
 a[B.Z].f=1000;
 printf("X: c=%c, i=%d, f=%f\nY: c=%c, i=%d, f=%f\nZ: c=%c, i=%d, f=%f\n",

a[B.X].c,a[B.X].i,a[B.X].f,a[B.Y].c,a[B.Y].i,a[B.Y].f,a[B.Z].c,a[B.Z].i,a[B.
Z].f);
}

Produces this output:

X: c=x, i=0, f=0.000000
Y: c= , i=-1, f=0.000000
Z: c= , i=0, f=1000.000000

Notice A is declared static, so I thought the default initializers would be used.

However, previously I was under the impression default struct initializers could be also used for non-static variables (then I read the docs and I discovered they were only for static variables). This leads me to this question: why can't they (initializers) be used for non-static variables?

-------------------------
Carlos Santander


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They should be. It's a bug. -Walter

Thank you!  I thought it was because it would cause hidden code to be generated.  ;)

Sean

"Walter" <walter@digitalmars.com> wrote in message news:bhro30$2663$1@digitaldaemon.com...
> They should be. It's a bug. -Walter