August 29, 2003
I'm getting the semantics of multidimensional arrays all messed up in my mind, and I need someone to help clarify something for me.

When declaring an array of strings, you're e3ssentially declaring a multi-dimensional array. But I always get my row-wise and my column-wise array accessing messed up. So, if I declare an array like this...

char[][] strings = ["zero", "one", "two", "three"];

..and I want to get the "one" entry into a new string, which of these do I use...

char[] x = strings[][1];
char[] x = strings[1][];
char[] x = strings[1];

I've been writing code exclusively in perl lately (a requirement for work (btw, I HATE perl's variable prefixes, using $ to dereference scalars from @ and % structures, not to mention the {} required to dereference a hash value)), and I'm having trouble remembering whether perl uses the same accessing order (row-wise? column-wise?) as Java or C. It's like somebody whacked me in the head with a stupid-stick.

--Benji Smith


August 30, 2003
"Benji Smith" <dlanguage@xxagg.com> wrote in message news:binldj$1uka$1@digitaldaemon.com...
> I'm getting the semantics of multidimensional arrays all messed up in my
mind,
> and I need someone to help clarify something for me.
>
> When declaring an array of strings, you're e3ssentially declaring a multi-dimensional array. But I always get my row-wise and my column-wise
array
> accessing messed up. So, if I declare an array like this...
>
> char[][] strings = ["zero", "one", "two", "three"];
>
> ..and I want to get the "one" entry into a new string, which of these do I use...
>
> char[] x = strings[][1];
> char[] x = strings[1][];
> char[] x = strings[1];

The 3rd one.