The .., range operator, when used like this :

string a = "abcd";
string b = a[0 .. a.count()-1];

sets b to "abc". is this the expected behavior?

On Friday, 8 August 2014 at 15:17:25 UTC, seany wrote:
> The .., range operator, when used like this :
>
> string a = "abcd";
> string b = a[0 .. a.count()-1];
>
> sets b to "abc". is this the expected behavior?

Yes. [..] is exclusive the last element.
So [0..1] is a single element [0]
That allows to avoid to always writing the "-1".
BTW: you can even use $ instead of a.count():
string b = a[0..$];
And if you like to slice the whole string, leave even the backets out:
string b = a;