http://d.puremagic.com/issues/show_bug.cgi?id=8289

           Summary: Cannot declare functions returning anonymous enum if
                    they have 'in' block.
           Product: D
           Version: D2
          Platform: All
        OS/Version: All
            Status: NEW
          Severity: minor
          Priority: P2
         Component: DMD
        AssignedTo: nobody@puremagic.com
        ReportedBy: mp81ss@rambler.ru


--- Comment #0 from Michele Pes <mp81ss@rambler.ru> 2012-06-23 07:11:50 PDT ---
import std.stdio;

enum { A, B };

/*
If I replace the return type int with enum, doesn't compile.
If I remove the in/body blocks and declare a contractless f, both enum/int are
ok.
*/
int dummy(in int i)
in {
    assert(i > 0);
}
body {
    return A;
}

void main()
{
    immutable x = dummy(0);
}

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http://d.puremagic.com/issues/show_bug.cgi?id=8289


Andrej Mitrovic <andrej.mitrovich@gmail.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|NEW                         |RESOLVED
                 CC|                            |andrej.mitrovich@gmail.com
         Resolution|                            |INVALID


--- Comment #1 from Andrej Mitrovic <andrej.mitrovich@gmail.com> 2012-12-02 06:07:23 PST ---
Maybe you're misreading the runtime assert error as a compiler error?

OTOH if you're trying to declare the return type as 'A', that won't work because A is not a type.

Unfortunately DMD allows nonsense like this:

enum dummy(in int i) { }

The 'enum' here acts as a placeholder as if you've declared it 'auto'.

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