Should this be allowed ?
--

import std.c.stdio;

void main ()
{

 const int option = 3;
 int assignAnInt = 0;

 switch (  option )
 {

  if (  true )
  {
   puts( "never executed" ) ;
  }

  assignAnInt = 21;

  case 3:
  puts( "3" );
  break;
  default:
  break;


 }

 printf( "%d",assignAnInt );

}

C wrote:

> Should this be allowed ?
[...]
>  switch (  option )
>  {
>   assignAnInt = 21;
>   case 3:
[...]

Yes.

It is the same as with:

void main(){
 if( true )
  printf("Not executed.\n");
 else
  printf("Executed.\n");
}

So long.

Hmm ?  I was refering to arbitrary code within the switch statement, not belonging to a case .  Its not correct code I thought the compiler would complain , however that also seems to be legal in C++.

#include <cstdio>
#include <cstdlib>

int main () {
 int option = 4;

 switch ( option ) {
  if ( option == 4 ) exit(0);

 case 4: puts("here");
 }

 return 1;
}

outputs : here

shrug,
C
"Manfred Nowak" <svv1999@hotmail.com> wrote in message
news:bvlf1b$m16$1@digitaldaemon.com...
> C wrote:
>
> > Should this be allowed ?
> [...]
> >  switch (  option )
> >  {
> >   assignAnInt = 21;
> >   case 3:
> [...]
>
> Yes.
>
> It is the same as with:
>
> void main(){
>  if( true )
>   printf("Not executed.\n");
>  else
>   printf("Executed.\n");
> }
>
> So long.

switch is just a shortcut for a lot of goto's to the different case-labels. so the behaviour is entierly understandable. it jumps over the rest to the first case that fits..

"C" <dont@respond.com> schrieb im Newsbeitrag news:bvmvfq$58e$1@digitaldaemon.com...
> Hmm ?  I was refering to arbitrary code within the switch statement, not belonging to a case .  Its not correct code I thought the compiler would complain , however that also seems to be legal in C++.
>
> #include <cstdio>
> #include <cstdlib>
>
> int main () {
>  int option = 4;
>
>  switch ( option ) {
>   if ( option == 4 ) exit(0);
>
>  case 4: puts("here");
>  }
>
>  return 1;
> }
>
> outputs : here
>
> shrug,
> C
> "Manfred Nowak" <svv1999@hotmail.com> wrote in message
> news:bvlf1b$m16$1@digitaldaemon.com...
> > C wrote:
> >
> > > Should this be allowed ?
> > [...]
> > >  switch (  option )
> > >  {
> > >   assignAnInt = 21;
> > >   case 3:
> > [...]
> >
> > Yes.
> >
> > It is the same as with:
> >
> > void main(){
> >  if( true )
> >   printf("Not executed.\n");
> >  else
> >   printf("Executed.\n");
> > }
> >
> > So long.
>
>

C wrote:

>Hmm ?  I was refering to arbitrary code within the switch statement, not
>belonging to a case .  Its not correct code I thought the compiler would
>complain , however that also seems to be legal in C++.
><snip>
>  
>
I didn't  realize that.  This means no-fall-through cases are possible in C++ (and C) ie

#define when(T) break;case T:

int main(int argc, char* argv[])
{
   int X = 5;
   switch (5)
   {
   when(5)
       printf("5\n");
   when(1)
       printf("1\n");
   }
   return 0;
}

-- 
-Anderson: http://badmama.com.au/~anderson/

C wrote:

> Its not correct code

It is correct code. If you look at the docs then you will see, that switchstatement derives to blockstatement and not something like casesequence.

So consecutive breakstatements are also correct. Also code between two breakstatements without a casestatement. And code after the last breakstatement also.

So long.