const bit mySwitch = true;
const bit[] mySwitches = [ true, false, false, true ];

int main()
{
mySwitch = false;       // "test.d(6): '1' is not an lvalue"
mySwitches[1] = true;   // compiles ok
return 0;
}

Same with v.77 and v.79

larry cowan wrote:

> const bit[] mySwitches = [ true, false, false, true ]; mySwitches[1] = true;   // compiles ok

Confirmed.

Moreover:
| mySwitches[4] = true;  // also compiles ok

And:
| printf("%u\n", myswitches[4]);
compiles also, however gives bounds checking error at runtime.

Note: I think there are 2 problems here:

1. The message "test.d(6): '1' is not an lvalue" is understandable (const
mySwitch has already been equated to true = 1), but not very apropos.

2. Allowing me to change const mySwitches array entries shouldn't be allowed
should it?, or do I have to "const" each entry somehow?
HELP!

"larry cowan" <larry_member@pathlink.com> modified his message news:bvs11e$1oc$1@digitaldaemon.com...
> const bit mySwitch = true;
> const bit[] mySwitches = [ true, false, false, true ];
>
> int main()
> {
   // mySwitch = false;       // "test.d(6): '1' is not an lvalue", if
compile attempted
> mySwitches[1] = true;   // compiles ok
   assert(mySwitches[1]);  // succeeds
> return 0;
> }
>
> Same with v.77 and v.79
>
>