What is a quick way to print a triangle? I'm thinking without foreach, not like I have here.

foreach(line; iota(1, 10 + 1)) {
	writeln("#".replicate(line));
}

These don't work:

iota(1, 10 + 1).
tee!((a) => { writeln("#".replicate(a)); });

string result;
iota(1, 10 + 1).
tee!((a) => result ~= "#".replicate(a) ~ "\n");
writeln(result);

On 29/04/2016 11:23 PM, Joel wrote:
> What is a quick way to print a triangle? I'm thinking without foreach,
> not like I have here.
>
> foreach(line; iota(1, 10 + 1)) {
>     writeln("#".replicate(line));
> }
>
> These don't work:
>
> iota(1, 10 + 1).
> tee!((a) => { writeln("#".replicate(a)); });
>
> string result;
> iota(1, 10 + 1).
> tee!((a) => result ~= "#".replicate(a) ~ "\n");
> writeln(result);

Not entirely the goal I'm guessing output wise, but this works.

import std.range : repeat;
foreach(line; 1 .. 11) {
	writeln('#'.repeat(line));
}

On Friday, 29 April 2016 at 11:31:51 UTC, rikki cattermole wrote:
> Not entirely the goal I'm guessing output wise, but this works.
>
> import std.range : repeat;
> foreach(line; 1 .. 11) {
> 	writeln('#'.repeat(line));
> }

That is shorter than my foreach version, but I want one that doesn't use foreach in it at all.

On Friday, 29 April 2016 at 12:01:19 UTC, Joel wrote:
> On Friday, 29 April 2016 at 11:31:51 UTC, rikki cattermole wrote:
>> Not entirely the goal I'm guessing output wise, but this works.
>>
>> import std.range : repeat;
>> foreach(line; 1 .. 11) {
>> 	writeln('#'.repeat(line));
>> }
>
> That is shorter than my foreach version, but I want one that doesn't use foreach in it at all.

Try this:

iota(1,11).each!(a => writeln("#".replicate(a)))

On Fri, Apr 29, 2016 at 12:01:19PM +0000, Joel via Digitalmars-d-learn wrote:
> On Friday, 29 April 2016 at 11:31:51 UTC, rikki cattermole wrote:
> >Not entirely the goal I'm guessing output wise, but this works.
> >
> >import std.range : repeat;
> >foreach(line; 1 .. 11) {
> >	writeln('#'.repeat(line));
> >}
> 
> That is shorter than my foreach version, but I want one that doesn't use foreach in it at all.

Try this:

	auto triangle(int i) {
		import std.algorithm.iteration : map, joiner;
		import std.range : iota, repeat;
		import std.utf : byCodeUnit; // this is a hack
		return iota(i).map!(i => '#'.repeat(i))
		              .joiner("\n".byCodeUnit);
	}
	void main() {
		import std.stdio : writeln;
		writeln(triangle(10));
	}

Unfortunately, due to some silly autodecoding issues in Phobos, byCodeUnit is a necessary hack to make this work. I'll file a bug for this.


T

-- 
Today's society is one of specialization: as you grow, you learn more and more about less and less. Eventually, you know everything about nothing.

On Fri, Apr 29, 2016 at 11:45:39AM -0700, H. S. Teoh via Digitalmars-d-learn wrote: [...]
> Unfortunately, due to some silly autodecoding issues in Phobos, byCodeUnit is a necessary hack to make this work. I'll file a bug for this.
[...]

https://issues.dlang.org/show_bug.cgi?id=15972


T

-- 
Skill without imagination is craftsmanship and gives us many useful objects such as wickerwork picnic baskets.  Imagination without skill gives us modern art. -- Tom Stoppard

[snip]

On Friday, 29 April 2016 at 13:20:47 UTC, Michael Coulombe wrote:
> Try this:
>
> iota(1,11).each!(a => writeln("#".replicate(a)))

Yes, this is what I was looking for!

It's my birthday today.