Im trying to iterate through a char[][]
with foreach.

It prints the correct amount of index's of "ch", but there is no value there.

ie: the following code prints

c =
c =
c =

names is a char[]
---------------------------------
 char[][] ch = split(names,"\n");
  foreach(char[] c; ch)
       {
             printf("c = \n", c);

         }

Any help is appreciated.

Phill.

Thats strange.......

ie: this prints fine
printf(c);

but this doesnt:
printf("c = \n", c);

Maybe I dont understand this printf :o((

Phill.


"Phill" <phill@pacific.net.au> wrote in message news:c2tgjg$2pqj$1@digitaldaemon.com...
> Im trying to iterate through a char[][]
> with foreach.
>
> It prints the correct amount of index's of "ch", but there is no value there.
>
> ie: the following code prints
>
> c =
> c =
> c =
>
> names is a char[]
> ---------------------------------
>  char[][] ch = split(names,"\n");
>   foreach(char[] c; ch)
>        {
>              printf("c = \n", c);
>
>          }
>
> Any help is appreciated.
>
> Phill.
>
>
>
>

On Sat, 13 Mar 2004 10:29:45 +1100, Phill wrote:

> Thats strange.......
> 
> ie: this prints fine
> printf(c);
> 
> but this doesnt:
> printf("c = \n", c);
> 
> Maybe I dont understand this printf :o((
> 
> Phill.

you forgot %c:
printf("c = %c\n", c);

Ant

I tried that but it doesnt print correctly ie:
It prints this:

c = ?
c =
c = #
c = $
c = %
c = !
c = )
c =
c =
c =
c = %
c =
c = (
c = (
c = $
c = ,
c = ,
c = !
c = ?
c = ?
c = "
c = !
c = $
c = &
c = ?
c = T
-------------
instead of this:
----------------------
200 digitalmars.com InterNetNews NNRP server INN 2.3.2 ready (posting ok).
Sending List request.....
215 Newsgroups in form "group high low flags".
c++ 0000003792 0000000001 y
c++.stl 0000000083 0000000001 y
c++.stl.hp 0000000010 0000000001 y
c++.stl.sgi 0000000039 0000000001 y
c++.stl.port 0000000176 0000000001 y
c++.idde 0000000402 0000000001 y
c++.command-line 0000000402 0000000001 y
c++.rtl 0000000059 0000000001 y
c++.mfc 0000000347 0000000001 y
c++.atl 0000000041 0000000001 y
c++.announce 0000000594 0000000001 y
c++.dos 0000000217 0000000001 y
c++.dos.16-bits 0000000156 0000000001 y
c++.dos.32-bits 0000000416 0000000001 y
c++.windows 0000000006 0000000001 y
c++.windows.16-bits 0000000071 0000000001 y
c++.windows.32-bits 0000000757 0000000001 y
c++.chat 0000000348 0000000001 y
D 0000025479 0000000001 y
D.gnu 0000000488 0000000001 y
DMDScript 0000000040 0000000001 y
c++.beta 0000000357 0000000001 y
c++.stlsoft 0000000188 0000000001 y
c++.wxwindows 0000000172 0000000001 y

It ok because printf(c) is fine for me I just wanted to see what I was getting back from the server, to see what I was dealing with.

I would be interested to find out the reason it is printing that though. I
dont know much  C/C++
so I only know that basics of printf.

Phill.


."Ant" <duitoolkit@yahoo.ca> wrote in message news:pan.2004.03.12.23.11.53.688428@yahoo.ca...
> On Sat, 13 Mar 2004 10:29:45 +1100, Phill wrote:
>
> > Thats strange.......
> >
> > ie: this prints fine
> > printf(c);
> >
> > but this doesnt:
> > printf("c = \n", c);
> >
> > Maybe I dont understand this printf :o((
> >
> > Phill.
>
> you forgot %c:
> printf("c = %c\n", c);
>
> Ant
>

Phill wrote:
> Im trying to iterate through a char[][]
> with foreach.
> 
> It prints the correct amount of index's of "ch", but there is no value
> there.
> 
> ie: the following code prints
> 
> c =
> c =
> c =
> 
> names is a char[]
> ---------------------------------
>  char[][] ch = split(names,"\n");
>   foreach(char[] c; ch)
>        {
>              printf("c = \n", c);

Try:
printf("%.*s = \n", c);

It's a char[] so "%.*s" it the proper format string.
(See also http://www.wikiservice.at/d/wiki.cgi?HowTo/printf)

> 
>          }
> 
> Any help is appreciated.
> 
> Phill.

Here's a full example, so that everyone can try it out:

import std.string;

void main()
{
 char[] names = "200 digitalmars.com InterNetNews NNRP server INN 2.3.2 ready (posting ok).
Sending List request.....
215 Newsgroups in form \"group high low flags\".
c++ 0000003792 0000000001 y
c++.stl 0000000083 0000000001 y
c++.stl.hp 0000000010 0000000001 y
c++.stl.sgi 0000000039 0000000001 y
c++.stl.port 0000000176 0000000001 y
c++.idde 0000000402 0000000001 y
c++.command-line 0000000402 0000000001 y
c++.rtl 0000000059 0000000001 y
c++.mfc 0000000347 0000000001 y
c++.atl 0000000041 0000000001 y
c++.announce 0000000594 0000000001 y
c++.dos 0000000217 0000000001 y
c++.dos.16-bits 0000000156 0000000001 y
c++.dos.32-bits 0000000416 0000000001 y
c++.windows 0000000006 0000000001 y
c++.windows.16-bits 0000000071 0000000001 y
c++.windows.32-bits 0000000757 0000000001 y
c++.chat 0000000348 0000000001 y
D 0000025479 0000000001 y
D.gnu 0000000488 0000000001 y
DMDScript 0000000040 0000000001 y
c++.beta 0000000357 0000000001 y
c++.stlsoft 0000000188 0000000001 y
c++.wxwindows 0000000172 0000000001 y";

 char[][] ch = split(names,"\n");
  foreach(char[] c; ch)
  {
    printf("%.*s = \n", c);
  }
}

-- 
Justin
http://jcc_7.tripod.com/d/

Phill wrote:

[...]
>   foreach(char[] c; ch)
>   {
>     printf("c = \n", c);
>   }
[...]

printf("c = %.*s\n", c);

There are some conventions most programmers trust in:

  `i' is a name used for a variable of integer type containing running
  content
  `n' is a name used for a variable of integer type containing an upper bound
  `c' is a name used for a variable of character type
  ...

So long.

On Sat, 13 Mar 2004 10:49:45 +1100, Phill <phill@pacific.net.au> wrote:

> I tried that but it doesnt print correctly ie:
> It prints this:
>
[...]
> -------------
> instead of this:
> ----------------------
[...]

Thats because c is of type char[].

instead of: printf("c = \n",c);

use this: printf("c = %*.s\n",c);

cya,
Andrew

On Fri, 12 Mar 2004 23:06:47 -0500, Andrew Edwards <remove_ridimz@remove_yahoo.com> wrote:

> On Sat, 13 Mar 2004 10:49:45 +1100, Phill <phill@pacific.net.au> wrote:
>
>> I tried that but it doesnt print correctly ie:
>> It prints this:
>>
> [...]
>> -------------
>> instead of this:
>> ----------------------
> [...]
>
> Thats because c is of type char[].
>
> instead of: printf("c = \n",c);
>
> use this: printf("c = %*.s\n",c);
>
> cya,
> Andrew

sorry, that should be %.*s

-- 
Using M2, Opera's revolutionary e-mail client: http://www.opera.com/m2/

"Manfred Nowak" <svv1999@hotmail.com> wrote in message news:c2tml8$383$1@digitaldaemon.com...
> Phill wrote:
>
> [...]
> >   foreach(char[] c; ch)
> >   {
> >     printf("c = \n", c);
> >   }
> [...]
>
> printf("c = %.*s\n", c);
>
> There are some conventions most programmers trust in:
>
>   `i' is a name used for a variable of integer type containing running
>   content
>   `n' is a name used for a variable of integer type containing an upper
bound
>   `c' is a name used for a variable of character type
>   ...
>
> So long.
>

Yes, and???

Phill

On Sat, 13 Mar 2004 15:31:51 +1100, Phill wrote:

> 
> "Manfred Nowak" <svv1999@hotmail.com> wrote in message news:c2tml8$383$1@digitaldaemon.com...
>> Phill wrote:
>>
>> [...]
>> >   foreach(char[] c; ch)
>> >   {
>> >     printf("c = \n", c);
>> >   }
>> [...]
>>
>> printf("c = %.*s\n", c);
>>
>> There are some conventions most programmers trust in:
>>
>>   `i' is a name used for a variable of integer type containing running
>>   content
>>   `n' is a name used for a variable of integer type containing an upper
> bound
>>   `c' is a name used for a variable of character type
>>   ...
>>
>> So long.
>>
> 
> Yes, and???
> 
> Phill

that's why my suggestions was wrong
I saw 'char' and 'c' so my brain ignored the '[]'
(actually I just looked at the printf and saw 'c')

You wouldn't do:

char[] myCharacter;
char myString;

would you?

Ant