The code

void foo(dchar [] string = BAR) {}
const dchar [] BAR = "Bar";

won't compile with the message

constchar.d(1): cannot implicitly convert expression (BAR) of type dchar[] to dchar[]

Funny, heh?

Anyway, it compiles if you switch the lines, so I suppose it's a wrongly diagnosed forward reference problem. The same bug appears if foo and BAR are members of a class.

Lars Ivar Igesund

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Lars Ivar Igesund schrieb am Sat, 09 Apr 2005 23:49:45 +0100:
> The code
>
> void foo(dchar [] string = BAR) {}
> const dchar [] BAR = "Bar";
>
> won't compile with the message
>
> constchar.d(1): cannot implicitly convert expression (BAR) of type dchar[] to dchar[]
>
> Funny, heh?
>
> Anyway, it compiles if you switch the lines, so I suppose it's a wrongly diagnosed forward reference problem. The same bug appears if foo and BAR are members of a class.

Added to DStress as http://dstress.kuehne.cn/run/default_argument_08.d http://dstress.kuehne.cn/run/default_argument_09.d

Thomas


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