Consider:

import std.traits;
class Foo
{
   void bar() {}
   void baz()() {}
}

This works:

static assert(isCallable!(Foo.bar));

This does not:

static assert(isCallable!(Foo.baz));

However, clearly I can call baz due to IFTI (with the equivalent syntax, someFoo.baz() or someFoo.baz). Is there a way to fix this?

-Steve

On Friday, 10 June 2016 at 17:32:03 UTC, Steven Schveighoffer wrote:
> Consider:
>
> import std.traits;
> class Foo
> {
>    void bar() {}
>    void baz()() {}
> }
>
> This works:
>
> static assert(isCallable!(Foo.bar));
>
> This does not:
>
> static assert(isCallable!(Foo.baz));
>
> However, clearly I can call baz due to IFTI (with the equivalent syntax, someFoo.baz() or someFoo.baz). Is there a way to fix this?
>
> -Steve

i guess thats the same reason that

isCallable!(unaryFun!someString) -> false

if not, then it probably would also be usefull if it would be evaluated to true.