Hi.

An error occurs in following codes at the time of compile. It checked with the Windows version compiler v0.109.

test.d
int main() {
uint a;

a = 1 << 31;
printf("%d\n", a);
return 0;
}

>dmd test.d
test.d(4): cannot implicitly convert expression 1 << 31 of type int to uint

Thanks,
Hiroshi Sakurai

---------------------------------
Japanese D wiki BugTrack http://f17.aaa.livedoor.jp/~labamba/?BugTrackhttp://f17.aaa.livedoor.jp/~labamba/?BugTrack%2F10

Added to DStress as
http://dstress.kuehne.cn/run/cast_06.d
http://dstress.kuehne.cn/run/cast_07.d

Thomas

I noticed this too.  Sometimes it'll say something like "Cannot convert 0xfffffffff093850a to uint", which leads me to believe that it's interpreting the constant as a long (64-bit int).  The 0.105 changelog says " Changed integral literal type determination to match C99 6.4.4.1."  Would be interesting to see if the bug is in 0.104 or 0.105 (I missed the DMD downloads for 0.103 through 0.108).

"Hiroshi Sakurai" <Hiroshi_member@pathlink.com> wrote in message news:cqtmid$3no$1@digitaldaemon.com...
> Hi.
>
> An error occurs in following codes at the time of compile. It checked with the Windows version compiler v0.109.
>
> test.d
> int main() {
> uint a;
>
> a = 1 << 31;
> printf("%d\n", a);
> return 0;
> }
>
> >dmd test.d
> test.d(4): cannot implicitly convert expression 1 << 31 of type int to
uint

That's right. The sign change changes the meaning, hence the message. I suggest rewriting to:

    1u << 31