Hi,

when I execute this code I have 7 7 7 as result, I think I understand why.

How can I execute a special task for one element ?

import std.stdio;
import std.parallelism;

void main(string[] args)
{
	class Account
	{
		public this(int id) { this.id = id; }
		int id;
	}

	Account[] accounts = [new Account(5), new Account(6), new Account(7)];

	foreach(acc; accounts)
	{
		task(() { writeln(acc.id); }).executeInNewThread();
	}
	
	readln();
}

Misu:

> void main(string[] args)
> {
> 	class Account
> 	{
> 		public this(int id) { this.id = id; }
> 		int id;
> 	}
> ...

This is not an answer to your question, but note:

void main() {
    class Foo {}
    static class Bar {}
    pragma(msg, __traits(classInstanceSize, Foo));
    pragma(msg, __traits(classInstanceSize, Bar));
}

Output:

12u
8u

Bye,
bearophile

On Thursday, 6 November 2014 at 10:53:32 UTC, Misu wrote:
> Hi,
>
> when I execute this code I have 7 7 7 as result, I think I understand why.
>
> How can I execute a special task for one element ?
>
> import std.stdio;
> import std.parallelism;
>
> void main(string[] args)
> {
> 	class Account
> 	{
> 		public this(int id) { this.id = id; }
> 		int id;
> 	}
>
> 	Account[] accounts = [new Account(5), new Account(6), new Account(7)];
>
> 	foreach(acc; accounts)
> 	{
> 		task(() { writeln(acc.id); }).executeInNewThread();
> 	}
> 	
> 	readln();
> }

It's a bug: https://issues.dlang.org/show_bug.cgi?id=2043

As a workaround, you can nest the call in another lambda:

    foreach(acc; accounts)
    {
        (Account acc) {
            task(() { writeln(acc.id); }).executeInNewThread();
        } (acc);
    }

On Thursday, 6 November 2014 at 13:04:18 UTC, Marc Schütz wrote:
> It's a bug: https://issues.dlang.org/show_bug.cgi?id=2043
>
> As a workaround, you can nest the call in another lambda:
>
>     foreach(acc; accounts)
>     {
>         (Account acc) {
>             task(() { writeln(acc.id); }).executeInNewThread();
>         } (acc);
>     }

Ok that's good. thank you !