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December 08, 2014 How do i use std.functional.binaryFun? | ||||
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How do i successfully use std.functional.binaryFun in the following example? import std.stdio; import std.functional; class Foo(T, alias greater = "a > b") if (is(typeof(binaryFun!(greater)(T.init, T.init)) == bool)) { private alias compare = binaryFun!(greater); public this() { writefln("%s", this.compare(2, 1)); } } void main(string[] args) { auto foo = new Foo!(int, "a < b"); // Works auto bar = new Foo!(int, delegate(int a, int b){ return a > b; }); // Linker error. } The first instantiation works when using a string but I get a linker error when i try and use a delegate as the compare function. Why is this? and what do i need to do to correct this? |
December 09, 2014 Re: How do i use std.functional.binaryFun? | ||||
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Posted in reply to Gary Willoughby | On Monday, 8 December 2014 at 20:08:35 UTC, Gary Willoughby wrote:
> import std.stdio;
> import std.functional;
>
> class Foo(T, alias greater = "a > b") if (is(typeof(binaryFun!(greater)(T.init, T.init)) == bool))
> {
> private alias compare = binaryFun!(greater);
>
> public this()
> {
> writefln("%s", this.compare(2, 1));
> }
> }
>
> void main(string[] args)
> {
> auto foo = new Foo!(int, "a < b"); // Works
>
> auto bar = new Foo!(int, delegate(int a, int b){ return a > b; }); // Linker error.
> }
Looks like a compiler bug.
A call without "this." works. When you insert a call without
"this.", other calls with "this." work, too.
A delegate with an implicit parameter type works: `Foo!(int,
delegate(int a, /*!*/ b){ return a > b;})`.
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December 09, 2014 Re: How do i use std.functional.binaryFun? | ||||
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Posted in reply to anonymous | On Tuesday, 9 December 2014 at 01:17:47 UTC, anonymous wrote: > Looks like a compiler bug. Filed: https://issues.dlang.org/show_bug.cgi?id=13843 |
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