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October 28, 2008 Initializing const member post-construction? | ||||
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Hi. I'm trying to port a C++ program to D as an exercise in exploring D. As I'm doing this, I've run into a bit of confusion with the const system. I have something like class A {} class B { const A a; void init(A aa) { a = aa; } } This doesn't work, because dmd (2.020) complains that you can't initialize a const member after the constructor. The catch is that the value of aa is not available at construction time, but only later on. However, I'd still like to declare that once set, the object referred to by a is const. The C++ code used a pointer, but it seemed to me like D's references were more capable than C++'s, so I'm trying to use them. To me it seems like this should still be allowed. Even though the object referred to by a is const, the reference itself shouldn't need to be. This seems morally equivalent to: const(A)* a; which is allowed by dmd. In both cases I'm trying to tell the compiler that the object referred to by a is const. Is there a way to do what I'm trying to do? What's the reason for not allowing this? Thanks, Jerry |
October 28, 2008 Re: Initializing const member post-construction? | ||||
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Posted in reply to Jerry Quinn | "Jerry Quinn" wrote > Hi. I'm trying to port a C++ program to D as an exercise in exploring D. As I'm doing this, I've run into a bit of confusion with the const system. > > I have something like > > class A {} > class B { > const A a; > void init(A aa) { a = aa; } > } > > This doesn't work, because dmd (2.020) complains that you can't initialize a const member after the constructor. The catch is that the value of aa is not available at construction time, but only later on. However, I'd still like to declare that once set, the object referred to by a is const. > > The C++ code used a pointer, but it seemed to me like D's references were more capable than C++'s, so I'm trying to use them. > > To me it seems like this should still be allowed. Even though the object referred to by a is const, the reference itself shouldn't need to be. This seems morally equivalent to: > > const(A)* a; > > which is allowed by dmd. In both cases I'm trying to tell the compiler that the object referred to by a is const. > > Is there a way to do what I'm trying to do? You can hide a behind a property: class B { private A aPriv; void init(A aa) { aPriv = aa; } const(A) a() const { return aPriv;} } Now, do not use aPriv anywhere else in your code, and you should be all set. Use -inline when compiling and you should see no performance penalty. > What's the reason for not allowing this? I was unaware you could even set a in the constructor. I don't think there's any general 'set once' type modifier. -Steve |
October 28, 2008 Re: Initializing const member post-construction? | ||||
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Posted in reply to Steven Schveighoffer | Steven Schveighoffer wrote:
> "Jerry Quinn" wrote
>> Hi. I'm trying to port a C++ program to D as an exercise in exploring D. As I'm doing this, I've run into a bit of confusion with the const system.
>>
>> I have something like
>>
>> class A {}
>> class B {
>> const A a;
>> void init(A aa) { a = aa; }
>> }
>>
>> This doesn't work, because dmd (2.020) complains that you can't initialize a const member after the constructor. The catch is that the value of aa is not available at construction time, but only later on. However, I'd still like to declare that once set, the object referred to by a is const.
>>
>> The C++ code used a pointer, but it seemed to me like D's references were more capable than C++'s, so I'm trying to use them.
>>
>> To me it seems like this should still be allowed. Even though the object referred to by a is const, the reference itself shouldn't need to be. This seems morally equivalent to:
>>
>> const(A)* a;
>>
>> which is allowed by dmd. In both cases I'm trying to tell the compiler that the object referred to by a is const.
>>
>> Is there a way to do what I'm trying to do?
>
> You can hide a behind a property:
>
> class B {
> private A aPriv;
> void init(A aa)
> {
> aPriv = aa;
> }
>
> const(A) a() const { return aPriv;}
> }
>
> Now, do not use aPriv anywhere else in your code, and you should be all set. Use -inline when compiling and you should see no performance penalty.
>
>> What's the reason for not allowing this?
>
> I was unaware you could even set a in the constructor. I don't think there's any general 'set once' type modifier.
>
> -Steve
Isn't that what 'final' is for? I can't seem to find any details on it in the D1 specs, but at least that's what it does in Java. I'm not sure it's implemented in D1 (yet?), though.
BTW, if you don't initialise a const member variable upon declaration, then it *must* be initialised in every constructor, I think.
-Lars
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October 28, 2008 Re: Initializing const member post-construction? | ||||
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Posted in reply to Lars Kyllingstad | "Lars Kyllingstad" wrote
> Steven Schveighoffer wrote:
>> "Jerry Quinn" wrote
>>> Hi. I'm trying to port a C++ program to D as an exercise in exploring D. As I'm doing this, I've run into a bit of confusion with the const system.
>>>
>>> I have something like
>>>
>>> class A {}
>>> class B {
>>> const A a;
>>> void init(A aa) { a = aa; }
>>> }
>>>
>>> This doesn't work, because dmd (2.020) complains that you can't initialize a const member after the constructor. The catch is that the value of aa is not available at construction time, but only later on. However, I'd still like to declare that once set, the object referred to by a is const.
>>>
>>> The C++ code used a pointer, but it seemed to me like D's references were more capable than C++'s, so I'm trying to use them.
>>>
>>> To me it seems like this should still be allowed. Even though the object referred to by a is const, the reference itself shouldn't need to be. This seems morally equivalent to:
>>>
>>> const(A)* a;
>>>
>>> which is allowed by dmd. In both cases I'm trying to tell the compiler that the object referred to by a is const.
>>>
>>> Is there a way to do what I'm trying to do?
>>
>> You can hide a behind a property:
>>
>> class B {
>> private A aPriv;
>> void init(A aa)
>> {
>> aPriv = aa;
>> }
>>
>> const(A) a() const { return aPriv;}
>> }
>>
>> Now, do not use aPriv anywhere else in your code, and you should be all set. Use -inline when compiling and you should see no performance penalty.
>>
>>> What's the reason for not allowing this?
>>
>> I was unaware you could even set a in the constructor. I don't think there's any general 'set once' type modifier.
>>
>> -Steve
>
> Isn't that what 'final' is for? I can't seem to find any details on it in the D1 specs, but at least that's what it does in Java. I'm not sure it's implemented in D1 (yet?), though.
Yes, I believe that is what final is for in D1. But the OP is using D2, and I believe that context for final was removed (it is now only used on member functions to mean that the function is no longer virtual).
-Steve
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October 29, 2008 Re: Initializing const member post-construction? | ||||
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Posted in reply to Steven Schveighoffer | Steven Schveighoffer Wrote: > "Jerry Quinn" wrote > > Hi. I'm trying to port a C++ program to D as an exercise in exploring D. As I'm doing this, I've run into a bit of confusion with the const system. > > > > I have something like > > > > class A {} > > class B { > > const A a; > > void init(A aa) { a = aa; } > > } > > > > This doesn't work, because dmd (2.020) complains that you can't initialize a const member after the constructor. The catch is that the value of aa is not available at construction time, but only later on. However, I'd still like to declare that once set, the object referred to by a is const. > > > > The C++ code used a pointer, but it seemed to me like D's references were more capable than C++'s, so I'm trying to use them. > > > > To me it seems like this should still be allowed. Even though the object referred to by a is const, the reference itself shouldn't need to be. This seems morally equivalent to: > > > > const(A)* a; > > > > which is allowed by dmd. In both cases I'm trying to tell the compiler that the object referred to by a is const. > > > > Is there a way to do what I'm trying to do? > > You can hide a behind a property: > > class B { > private A aPriv; > void init(A aa) > { > aPriv = aa; > } > > const(A) a() const { return aPriv;} > } > > Now, do not use aPriv anywhere else in your code, and you should be all set. Use -inline when compiling and you should see no performance penalty. Yes, that seems to be a reasonable workaround. Thanks. > > What's the reason for not allowing this? > > I was unaware you could even set a in the constructor. I don't think there's any general 'set once' type modifier. No, I didn't see one either. In fact what I was asking for is not a set once. It's to allow a reference to a const object to be reassigned, since it wasn't obvious to me that the reference itself should be kept const. Jerry |
October 29, 2008 Re: Initializing const member post-construction? | ||||
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Posted in reply to Jerry Quinn | "Jerry Quinn" wrote
> Steven Schveighoffer Wrote:
>> I was unaware you could even set a in the constructor. I don't think there's any general 'set once' type modifier.
>
> No, I didn't see one either. In fact what I was asking for is not a set once. It's to allow a reference to a const object to be reassigned, since it wasn't obvious to me that the reference itself should be kept const.
Oh, for this there is std.typecons.Rebindable:
Rebindable!(const(A)) a;
Not sure how close it is to the real thing, I haven't used it.
-Steve
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