November 04, 2008
With D1, if I define an opAssign for a struct, I can still access the blitting version by just assigning to another instance of the same struct.

i.e.:

struct S
{
   int x;
   S opAssign(int n) {x = n; return *this;}
}

void foo(S s)
{
   S s2;
   s2 = s; // ok, just does a bitcopy
}

However, in D2.019 (not sure when this was added), I now get a compile error for the assignment statement:

function testit.S.opAssign (int n) does not match parameter types (S)
Error: cannot implicitly convert expression (s) of type S to int

I have to define opAssign(S s).  The docs still say it's not allowed, but apparently it is necessary.

Is there any way to call the default bitcopy from this overloaded opAssign, or flag that a struct should just be bitcopied when being assigned?

-Steve


November 06, 2008
Does nobody have an answer to this?  I guess I'll file a bug report.

-Steve

"Steven Schveighoffer" wrote
> Is there any way to call the default bitcopy from this overloaded opAssign, or flag that a struct should just be bitcopied when being assigned?