I call readln() on a variable in a loop. On the next iteration, it's as if the readln() is ignored, as it moves on to the next line apparently. Here is the code:

for(int i = 1;i<1000;i++)
    {
        int tempx;
        int tempy;
        int high = 0;
        double highs = 0;
        writeln("Type in  data for an egg:");
        write("Chicken: ");
        readln(tempz);
        write("Width: ");
        readf(" %d",&tempx);
        write("Hight: ");
        readf(" %d",&tempy);
        data[i] = new egg(tempx,tempy,cast(string)tempz);
//...
Anything that will fix this?

On Thursday, 28 January 2021 at 19:25:52 UTC, Ruby The Roobster wrote:
> I call readln() on a variable in a loop. On the next iteration, it's as if the readln() is ignored, as it moves on to the next line apparently. Here is the code:
>
> for(int i = 1;i<1000;i++)
>     {
>         int tempx;
>         int tempy;
>         int high = 0;
>         double highs = 0;
>         writeln("Type in  data for an egg:");
>         write("Chicken: ");
>         readln(tempz);
>         write("Width: ");
>         readf(" %d",&tempx);
>         write("Hight: ");
>         readf(" %d",&tempy);
>         data[i] = new egg(tempx,tempy,cast(string)tempz);
> //...
> Anything that will fix this?

Here is the declaration for tempz(outside the loop): char[] tempz;

On Thursday, 28 January 2021 at 19:25:52 UTC, Ruby The Roobster wrote:
>         readf(" %d",&tempy);

This leaves the \n at the end. A next readf thanks to the leading space would ignore that \n and keep going, but a readln stops at the first \n it sees, even if it is a leftover item in the buffer from a readf before.

On Thursday, 28 January 2021 at 19:31:35 UTC, Adam D. Ruppe wrote:
> On Thursday, 28 January 2021 at 19:25:52 UTC, Ruby The Roobster wrote:
>>         readf(" %d",&tempy);
>
> This leaves the \n at the end. A next readf thanks to the leading space would ignore that \n and keep going, but a readln stops at the first \n it sees, even if it is a leftover item in the buffer from a readf before.

I replaced readln with the following: readf(" %s\n",&tempz);
That seemed to do the trick(and note here, when you press enter, it stops taking input).