Hi,

in this minified example I try to expand the variadic parmaters of
foo to bar:

import std.typecons;

void foo(T ...)(T args)
{
     bar(args.expand);
}

void bar(int i, string s){}

void main()
{
	foo(1, "a");
}

I got the syntax error: no property 'expand' for type '(int,
string)'
I understand args is a TypeTuple and therefore expand is not
working.
Is there a simple way to get it working?

Kind regards
André

On Tue, 10 Mar 2015 19:11:21 +0000, André wrote:

> Hi,
> 
> in this minified example I try to expand the variadic parmaters of foo to bar:
> 
> import std.typecons;
> 
> void foo(T ...)(T args)
> {
>       bar(args.expand);
> }
> 
> void bar(int i, string s){}
> 
> void main()
> {
> 	foo(1, "a");
> }
> 
> I got the syntax error: no property 'expand' for type '(int, string)' I understand args is a TypeTuple and therefore expand is not working. Is there a simple way to get it working?

sure. just remove `.expand`. ;-)

  void foo(T...) (T args) {
    bar(args);
  }

On Tuesday, 10 March 2015 at 19:11:22 UTC, André wrote:
> Is there a simple way to get it working?

The simplest: just write `bar(args);` - the variadic arguments will automatically expand.

too many trees in front of my eyes.
Thanks for the answers.

Kind regards
André

On Tuesday, 10 March 2015 at 19:16:23 UTC, Adam D. Ruppe wrote:
> On Tuesday, 10 March 2015 at 19:11:22 UTC, André wrote:
>> Is there a simple way to get it working?
>
> The simplest: just write `bar(args);` - the variadic arguments will automatically expand.

On Tuesday, 10 March 2015 at 19:11:22 UTC, André wrote:
> Hi,
>
> in this minified example I try to expand the variadic parmaters of
> foo to bar:
>
> import std.typecons;
>
> void foo(T ...)(T args)
> {
>      bar(args.expand);
> }
>
> void bar(int i, string s){}
>
> void main()
> {
> 	foo(1, "a");
> }
>
> I got the syntax error: no property 'expand' for type '(int,
> string)'
> I understand args is a TypeTuple and therefore expand is not
> working.
> Is there a simple way to get it working?
>
> Kind regards
> André

Just to be clear, TypeTuple is a library construct defined in std.typetuple. It doesn't have a .expand member as far as I know. You're probably thinking of tuple.expand.

The type of `T ...` is not TypeTuple, but an internal tuple type used by the compiler. TypeTuple is just some syntactic sugar allowing you to create one of these compiler tuples.