How can I reach something like below code:

int a=1;
int b=2;
int c=(int a,int b){
   return a+b;}
writefln("Result:%d",c);

Thanks in advance.

Sam Hu wrote:
> How can I reach something like below code:
> 
> int a=1;
> int b=2;
> int c=(int a,int b){
>    return a+b;}
> writefln("Result:%d",c);
> 
> Thanks in advance.

You need to call the delegate you've made.

int a=1;
int b=2;
int c=(int a,int b){
   return a+b;}(a,b);
writefln("Result:%d",c);}

On Thu, 12 Nov 2009 10:21:44 -0500, Don <nospam@nospam.com> wrote:

> Sam Hu wrote:
>> How can I reach something like below code:
>>  int a=1;
>> int b=2;
>> int c=(int a,int b){
>>    return a+b;}
>> writefln("Result:%d",c);
>>  Thanks in advance.
>
> You need to call the delegate you've made.
>
> int a=1;
> int b=2;
> int c=(int a,int b){
>     return a+b;}(a,b);
> writefln("Result:%d",c);}

Also, don't forget you can refer to variables in the enclosing function:

int c = (){return a + b;}();

-Steve

Steven Schveighoffer:

> int c = (){return a + b;}();

You can also write:
int c = {return a + b;}();

Bye,
bearophile

bearophile wrote:
> Steven Schveighoffer:
> 
>> int c = (){return a + b;}();
> 
> You can also write:
> int c = {return a + b;}();
> 
> Bye,
> bearophile

Shorter:

int c = a + b;

Don Wrote:

> You need to call the delegate you've made.

I missed this key point.

So to summary:
int a=1;
int b=2;
1.nested function;
2.int c=(int a,int b){return a+b;}(a,b);
3.int c=(int,int){return a+b;}(a,b);
4.int c=(){return a+b;}();
5.int c={return a+b;}();

How come the last one is legal?

Thank you all for all your help!

Hello Sam,

> Don Wrote:
> 
>> You need to call the delegate you've made.
>> 
> I missed this key point.
> 
> So to summary:
> int a=1;
> int b=2;
> 1.nested function;
> 2.int c=(int a,int b){return a+b;}(a,b);
> 3.int c=(int,int){return a+b;}(a,b);
> 4.int c=(){return a+b;}();
> 5.int c={return a+b;}();
> How come the last one is legal?

If the function has no args the first () can be dropped.
If the return type can be inferred, that can be dropped.
Nested functions can access vars in the outer function.

> 
> Thank you all for all your help!
> 

BCS Wrote:

> If the function has no args the first () can be dropped.
> If the return type can be inferred, that can be dropped.
> Nested functions can access vars in the outer function.
> 

Got it.Thanks a lot!