While trying to create a safe int, I have found a problem, this is reduced code:

struct Foo {
    int x;
    static Foo opAssign(int value) { return Foo(value); }
}
void main() {
    Foo y = 0;
}


The compiler prints:
test.d(6): Error: cannot implicitly convert expression (0) of type int to Foo

While this generates no error:
Foo y; y = 0; is OK.

Do you know if there is a way to do that?

Bye and thank you,
bearophile

On 03/11/2010 11:22 AM, bearophile wrote:
> While trying to create a safe int, I have found a problem, this is reduced code:
>
> struct Foo {
>      int x;
>      static Foo opAssign(int value) { return Foo(value); }
> }
> void main() {
>      Foo y = 0;
> }
>
>
> The compiler prints:
> test.d(6): Error: cannot implicitly convert expression (0) of type int to Foo
>
> While this generates no error:
> Foo y; y = 0; is OK.
>
> Do you know if there is a way to do that?
>
> Bye and thank you,
> bearophile

define opCall in Foo

Ellery Newcomer:
> define opCall in Foo

Thank you :-)
I need to practice more with operator overload.

Bye,
bearophile

On 03/11/2010 06:22 PM, bearophile wrote:
> While trying to create a safe int, I have found a problem, this is reduced code:
>
> struct Foo {
>      int x;
>      static Foo opAssign(int value) { return Foo(value); }
> }
> void main() {
>      Foo y = 0;
> }
>
>
> The compiler prints:
> test.d(6): Error: cannot implicitly convert expression (0) of type int to Foo
>
> While this generates no error:
> Foo y; y = 0; is OK.
>
> Do you know if there is a way to do that?
>
> Bye and thank you,
> bearophile

I think you want a constructor.

struct Foo {
    int x;
    static Foo opAssign(int value) { return Foo(value); }
    this(int i) {x = i;}
}