Thread overview
[Issue 1373] New: typeof(func).stringof fails when func has parameters.
Jul 25, 2007
d-bugmail
Aug 31, 2007
Reiner Pope
Oct 21, 2007
d-bugmail
Oct 23, 2007
d-bugmail
Apr 26, 2010
Harry Vennik
Jul 02, 2011
Walter Bright
July 25, 2007
http://d.puremagic.com/issues/show_bug.cgi?id=1373

           Summary: typeof(func).stringof   fails when func has parameters.
           Product: D
           Version: 1.019
          Platform: PC
        OS/Version: Windows
            Status: NEW
          Severity: normal
          Priority: P2
         Component: DMD
        AssignedTo: bugzilla@digitalmars.com
        ReportedBy: clugdbug@yahoo.com.au


If func is a function (not a function pointer) with zero arguments, it works
correctly (I think). But if it is a function with >0 arguments, then it
complains that it cannot evaluate it.

Curiously, it generates the correct result, as evidenced by pragma(msg) below, before giving the error.

--------------
double func0() { return 0; }
int func2(int a, int b) { return 2; }

void main()
{
    static assert(typeof(func0).stringof=="(double())()"); // OK
    pragma(msg, typeof(func2).stringof);
    // bug.d(8): Error: expected 2 arguments, not 0
    // (int(int a, int b))()
    static assert(typeof(func2).stringof=="(int(int a, int b))()");
}


-- 

August 31, 2007
d-bugmail@puremagic.com wrote:
> http://d.puremagic.com/issues/show_bug.cgi?id=1373
> 
>            Summary: typeof(func).stringof   fails when func has parameters.
>            Product: D
>            Version: 1.019
>           Platform: PC
>         OS/Version: Windows
>             Status: NEW
>           Severity: normal
>           Priority: P2
>          Component: DMD
>         AssignedTo: bugzilla@digitalmars.com
>         ReportedBy: clugdbug@yahoo.com.au
> 
> 
> If func is a function (not a function pointer) with zero arguments, it works
> correctly (I think). But if it is a function with >0 arguments, then it
> complains that it cannot evaluate it.
> 
> Curiously, it generates the correct result, as evidenced by pragma(msg) below,
> before giving the error.
> 
> --------------
> double func0() { return 0; }
> int func2(int a, int b) { return 2; }
> 
> void main()
> {      static assert(typeof(func0).stringof=="(double())()"); // OK
>     pragma(msg, typeof(func2).stringof);
>     // bug.d(8): Error: expected 2 arguments, not 0
>     // (int(int a, int b))()
>     static assert(typeof(func2).stringof=="(int(int a, int b))()");
> }
> 
> 

I think a related issue is


void func(int) {}

const text = func.stringof;

which doesn't compile under 2.003, error message: "func_stringof.func(int) does not match parameter types ()".

However, it works if the int parameter is removed.
October 21, 2007
http://d.puremagic.com/issues/show_bug.cgi?id=1373


smjg@iname.com changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |smjg@iname.com




------- Comment #2 from smjg@iname.com  2007-10-21 11:08 -------
Please don't blindly quote the entire message when replying.  It's bad enough on any newsgroup, and when it clutters up Bugzilla, it's even worse.

This issue is puzzling me.  Surely typeof(func0) should be double, since as an
expression, func0 is equivalent to func0().  And typeof(func2) probably
shouldn't compile.


-- 

October 23, 2007
http://d.puremagic.com/issues/show_bug.cgi?id=1373





------- Comment #3 from clugdbug@yahoo.com.au  2007-10-23 10:49 -------
(In reply to comment #2)
> Please don't blindly quote the entire message when replying.  It's bad enough on any newsgroup, and when it clutters up Bugzilla, it's even worse.
> 
> This issue is puzzling me.  Surely typeof(func0) should be double, since as an
> expression, func0 is equivalent to func0().  And typeof(func2) probably
> shouldn't compile.

Function types _are_ wierd. And not well documented.

What is func2 ? It's a symbol of "function type". The only thing you do with it it takes its address. Since in the spec, it's allowable in  & UnaryExpression, it must be an expression, but I can't see it listed there.

Definitely related to issue #1341.


-- 

April 26, 2010
http://d.puremagic.com/issues/show_bug.cgi?id=1373


Harry Vennik <htvennik@zonnet.nl> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |htvennik@zonnet.nl


--- Comment #4 from Harry Vennik <htvennik@zonnet.nl> 2010-04-26 06:20:08 PDT ---
This issue bugged me with DMD 2.043 on Mac.

I noticed something peculiar which is demonstrated by this test case:

-----
void foo(int i) { }
enum string FOO_TYPE = typeof(foo).stringof;
pragma(msg, "Type of foo is: " ~ FOO_TYPE);
-----

Compiling that will print:

-----
stringof_error.d(2): Error: expected 1 function arguments, not 0
Type of foo is: (void(int i))()
-----

So actually, the .stringof is correctly evaluated, but still some unnecessary check for function arguments makes the compiler generate an error.

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July 02, 2011
http://d.puremagic.com/issues/show_bug.cgi?id=1373


Walter Bright <bugzilla@digitalmars.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|NEW                         |RESOLVED
                 CC|                            |bugzilla@digitalmars.com
         Resolution|                            |FIXED


--- Comment #5 from Walter Bright <bugzilla@digitalmars.com> 2011-07-01 22:13:17 PDT ---
https://github.com/D-Programming-Language/dmd/commit/28702b21e143807205f6798b000a0c05bb22d5e2

https://github.com/D-Programming-Language/dmd/commit/23bef66be596ab4541fe26a5433f8cdbd92fc4ac

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