Hello, people!


The following case:
-------------------
int var = floor(sqrt(n)) // where 'n' is a 'const int'

Produces the following error:
-----------------------------
Error: std.math.sqrt called with argument types (const(int)) matches both:
/usr/include/dmd/phobos/std/math.d(2067):     std.math.sqrt(float x)
and:
/usr/include/dmd/phobos/std/math.d(2073):     std.math.sqrt(real x)


Please, could you tell me how do I solve this?!

Thank you!

On Tuesday, 11 December 2018 at 14:16:05 UTC, Narxa wrote:
> int var = floor(sqrt(n)) // where 'n' is a 'const int'

You can just cast it to float:

floor(sqrt( cast(float) n ));

and it will work.

On Tuesday, 11 December 2018 at 14:22:30 UTC, Adam D. Ruppe wrote:
> On Tuesday, 11 December 2018 at 14:16:05 UTC, Narxa wrote:
>> int var = floor(sqrt(n)) // where 'n' is a 'const int'
>
> You can just cast it to float:
>
> floor(sqrt( cast(float) n ));
>
> and it will work.

It produced the following error:
--------------------------------
Error: cannot implicitly convert expression floor(sqrt(cast(float)n)) of type float to int


I am using 'dmd' compiler if it matters.

On 12/11/18 9:47 AM, Narxa wrote:
> On Tuesday, 11 December 2018 at 14:22:30 UTC, Adam D. Ruppe wrote:
>> On Tuesday, 11 December 2018 at 14:16:05 UTC, Narxa wrote:
>>> int var = floor(sqrt(n)) // where 'n' is a 'const int'
>>
>> You can just cast it to float:
>>
>> floor(sqrt( cast(float) n ));
>>
>> and it will work.
> 
> It produced the following error:
> --------------------------------
> Error: cannot implicitly convert expression floor(sqrt(cast(float)n)) of type float to int
> 
> 
> I am using 'dmd' compiler if it matters.

You need to cast the result back to int.

-Steve

On Tuesday, 11 December 2018 at 14:53:02 UTC, Steven Schveighoffer wrote:
> On 12/11/18 9:47 AM, Narxa wrote:
>> On Tuesday, 11 December 2018 at 14:22:30 UTC, Adam D. Ruppe wrote:
>>> On Tuesday, 11 December 2018 at 14:16:05 UTC, Narxa wrote:
>>>> int var = floor(sqrt(n)) // where 'n' is a 'const int'
>>>
>>> You can just cast it to float:
>>>
>>> floor(sqrt( cast(float) n ));
>>>
>>> and it will work.
>> 
>> It produced the following error:
>> --------------------------------
>> Error: cannot implicitly convert expression floor(sqrt(cast(float)n)) of type float to int
>> 
>> 
>> I am using 'dmd' compiler if it matters.
>
> You need to cast the result back to int.
>
> -Steve

Yes, it worked:
---------------
int var = cast(int) floor(sqrt( cast(float) n ));


I thought floor already returned an 'int' but I was mistaken.

Thank you very much.

On Tuesday, 11 December 2018 at 15:17:10 UTC, Narxa wrote:
> Yes, it worked:
> ---------------
> int var = cast(int) floor(sqrt( cast(float) n ));
>
>
> I thought floor already returned an 'int' but I was mistaken.
>
> Thank you very much.

I think you don't need floor.

int var = cast(int)(sqrt(cast(float)n));

or:

int var = cast(int)(float(i).sqrt);

or:

int var = float(i).sqrt.to!int;

Andrea