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May 13, 2011 Correctness bug in TDPL | ||||
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On p368 the CheckedInt struct does not check for overflow in the unary minus operator. |
May 13, 2011 Re: Correctness bug in TDPL | ||||
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Posted in reply to Timon Gehr | On 5/13/11 3:25 AM, Timon Gehr wrote:
> On p368 the CheckedInt struct does not check for overflow in the unary minus
> operator.
Unary minus never overflows. That being said, there is the oddity that -x is x when x == int.min. Even in that case there is no loss of information.
Andrei
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May 13, 2011 Re: Correctness bug in TDPL | ||||
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Posted in reply to Andrei Alexandrescu | > On 5/13/11 3:25 AM, Timon Gehr wrote: > > On p368 the CheckedInt struct does not check for overflow in the unary minus operator. > > Unary minus never overflows. That being said, there is the oddity that -x is x when x == int.min. Even in that case there is no loss of information. > > Andrei This behavior is caused by _overflow_ when the error condition that is checked in ++ is overflow: auto x=CheckedInt(int.min); x=-x; //passes x=~x; x++;//throws Also, the statement that there is no loss of information is just wrong: scanf("%d %d %d",&n_,&m_); auto n=CheckedInt!int(n_),m=CheckedInt!int(m_); enforce(n>0 && m<0, "provide meaningful input!"); foreach(i;0..n) m=-m; writeln(n," is"~(m<0?"odd":"even")); //disaster strikes! Timon |
May 13, 2011 Re: Correctness bug in TDPL | ||||
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Posted in reply to Timon Gehr | On 5/13/11 1:01 PM, Timon Gehr wrote: >> On 5/13/11 3:25 AM, Timon Gehr wrote: >>> On p368 the CheckedInt struct does not check for overflow in the unary minus >>> operator. >> >> Unary minus never overflows. That being said, there is the oddity that >> -x is x when x == int.min. Even in that case there is no loss of >> information. >> >> Andrei > > This behavior is caused by _overflow_ when the error condition that is checked in > ++ is overflow: > > auto x=CheckedInt(int.min); > x=-x; //passes > > x=~x; > x++;//throws Not sure I understand the point here. I do agree that this may be confusing and also that it's reasonable to check against int.min in unary minus. > Also, the statement that there is no loss of information is just wrong: > > scanf("%d %d %d",&n_,&m_); > auto n=CheckedInt!int(n_),m=CheckedInt!int(m_); > enforce(n>0&& m<0, "provide meaningful input!"); > foreach(i;0..n) m=-m; > writeln(n," is"~(m<0?"odd":"even")); //disaster strikes! Depends on how one defines "information". I meant it simply as state available to the program. Andrei |
May 13, 2011 Re: Correctness bug in TDPL | ||||
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Posted in reply to Andrei Alexandrescu | Andrei Alexandrescu wrote: >On 5/13/11 1:01 PM, Timon Gehr wrote: >>> On 5/13/11 3:25 AM, Timon Gehr wrote: >>>> On p368 the CheckedInt struct does not check for overflow in the unary minus operator. >>> >>> Unary minus never overflows. That being said, there is the oddity that -x is x when x == int.min. Even in that case there is no loss of information. >>> >>> Andrei >> >> This behavior is caused by _overflow_ when the error condition that is checked in ++ is overflow: >> >> auto x=CheckedInt(int.min); >> x=-x; //passes >> >> x=~x; >> x++;//throws > > Not sure I understand the point here. I do agree that this may be confusing and also that it's reasonable to check against int.min in unary minus. In two's complement, -x is the same as ~x+1. The implementation in TDPL says one is correct and the other is wrong on int.min. My understanding is that something that claims to be a CheckedInt has exactly two options on every operation: 1. Behave like a pure whole number, without any strange corner cases. 2. Throw an exception. struct CheckedInt in TDPL does not guarantee that. This means it basically gives no reasonable guarantee. You may disagree on this but in my eyes it is a serious bug. > >> Also, the statement that there is no loss of information is just wrong: >> >> scanf("%d %d %d",&n_,&m_); >> auto n=CheckedInt!int(n_),m=CheckedInt!int(m_); >> enforce(n>0&& m<0, "provide meaningful input!"); >> foreach(i;0..n) m=-m; >> writeln(n," is"~(m<0?"odd":"even")); //disaster strikes! > > Depends on how one defines "information". I meant it simply as state available to the program. Okay. But I think this is not really applicable to CheckedInt. By this definition the fact that int.max+1==int.min is just another oddity (when inspected nearer it is even just the same oddity), not overflow that loses information. TDPL checks for that though. > > > Andrei But it is of course up to you if you consider this a worthy addition to some future version of TDPL. Timon OT: I got one of those without an author on it. =) How many are there of those? BTW, it is one of the best reads I've had! |
May 13, 2011 Re: Correctness bug in TDPL | ||||
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Posted in reply to Timon Gehr | On 5/13/11 5:29 PM, Timon Gehr wrote: > Andrei Alexandrescu wrote: >> On 5/13/11 1:01 PM, Timon Gehr wrote: >>>> On 5/13/11 3:25 AM, Timon Gehr wrote: >>>>> On p368 the CheckedInt struct does not check for overflow in the unary minus >>>>> operator. >>>> >>>> Unary minus never overflows. That being said, there is the oddity that >>>> -x is x when x == int.min. Even in that case there is no loss of >>>> information. >>>> >>>> Andrei >>> >>> This behavior is caused by _overflow_ when the error condition that is checked in >>> ++ is overflow: >>> >>> auto x=CheckedInt(int.min); >>> x=-x; //passes >>> >>> x=~x; >>> x++;//throws >> >> Not sure I understand the point here. I do agree that this may be >> confusing and also that it's reasonable to check against int.min in >> unary minus. > > In two's complement, -x is the same as ~x+1. The implementation in TDPL says one > is correct and the other is wrong on int.min. Now I understand. Thanks for clarifying. I updated the errata with credit and with a reference to this discussion: http://erdani.com/tdpl/errata > My understanding is that something that claims to be a CheckedInt has exactly two > options on every operation: > > 1. Behave like a pure whole number, without any strange corner cases. > 2. Throw an exception. > > struct CheckedInt in TDPL does not guarantee that. > This means it basically gives no reasonable guarantee. You may disagree on this > but in my eyes it is a serious bug. > >> >>> Also, the statement that there is no loss of information is just wrong: >>> >>> scanf("%d %d %d",&n_,&m_); >>> auto n=CheckedInt!int(n_),m=CheckedInt!int(m_); >>> enforce(n>0&& m<0, "provide meaningful input!"); >>> foreach(i;0..n) m=-m; >>> writeln(n," is"~(m<0?"odd":"even")); //disaster strikes! >> >> Depends on how one defines "information". I meant it simply as state >> available to the program. > > Okay. But I think this is not really applicable to CheckedInt. By this definition > the fact that int.max+1==int.min is just another oddity (when inspected nearer it > is even just the same oddity), not overflow that loses information. TDPL checks > for that though. > >> >> >> Andrei > > But it is of course up to you if you consider this a worthy addition to some > future version of TDPL. It definitely is. I appreciate you followed through and explained the matter to me. > Timon > > > OT: I got one of those without an author on it. =) How many are there of those? > BTW, it is one of the best reads I've had! Thanks very much! There were like 1830 copies without an author's name on the cover, they are now getting hard to find. Andrei |
February 10, 2013 Re: Correctness bug in TDPL | ||||
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Posted in reply to Andrei Alexandrescu | On Friday, 13 May 2011 at 13:36:13 UTC, Andrei Alexandrescu wrote:
> On 5/13/11 3:25 AM, Timon Gehr wrote:
>> On p368 the CheckedInt struct does not check for overflow in the unary minus
>> operator.
>
> Unary minus never overflows. That being said, there is the oddity that -x is x when x == int.min. Even in that case there is no loss of information.
>
> Andrei
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