http://d.puremagic.com/issues/show_bug.cgi?id=5821

           Summary: Calling spawn in std.concurrency without all the
                    parameters required by void function(T) fn
           Product: D
           Version: D2
          Platform: x86
        OS/Version: Linux
            Status: NEW
          Severity: normal
          Priority: P2
         Component: Phobos
        AssignedTo: nobody@puremagic.com
        ReportedBy: jsancio@gmail.com


--- Comment #0 from Jose Garcia <jsancio@gmail.com> 2011-04-08 13:33:50 PDT ---
I am not sure if this a language, compiler, or library issue but when you call spawn without passing all the parameters required by the fn it can either segfault if you are lucky or worst yet have an unpredictable behavior.

For example the following code will compile and execute:

import std.concurrency;

void main()
{
   spawn(&fun);
}

void fun(int i) {}

My intuition is that the code above should not compile.

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Andriy <andrden@gmail.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
                 CC|                            |andrden@gmail.com


--- Comment #1 from Andriy <andrden@gmail.com> 2011-04-12 08:55:29 PDT ---
Seems more like it's language:
  arg: 100
  arg: 134851556 (any number actually)
is printed by the following which should not compile:

import std.stdio;

void func(int value){
    writeln("arg: ",value);
}

void myspawn(T...)( void function(T) fn, T args ){
    fn(args);
}

void main(){
    myspawn(&func,100);
    myspawn(&func);
}

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yebblies <yebblies@gmail.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|NEW                         |RESOLVED
                 CC|                            |yebblies@gmail.com
         Resolution|                            |DUPLICATE


--- Comment #2 from yebblies <yebblies@gmail.com> 2011-06-04 22:52:55 PDT ---
With only the function pointer as an argument, spawn becomes:
void spawn(void function() fn)
and &fun is (incorrectly) implicitly converted to void function() fn.

*** This issue has been marked as a duplicate of issue 3797 ***

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