std.conv does not support conversion from a hexadecimal string to an integer. Is there a technical reason for this limitation?

This is the best I could do, can it be improved still?
int i = to!int(parse!float("0x1ap0"));

On 8/2/2011 8:17 PM, Stijn Herreman wrote:
> std.conv does not support conversion from a hexadecimal string to an
> integer. Is there a technical reason for this limitation?
>
> This is the best I could do, can it be improved still?
> int i = to!int(parse!float("0x1ap0"));

parse!int("1a", 16);

On 3/08/2011 2:32, Johann MacDonagh wrote:
> On 8/2/2011 8:17 PM, Stijn Herreman wrote:
>> std.conv does not support conversion from a hexadecimal string to an
>> integer. Is there a technical reason for this limitation?
>>
>> This is the best I could do, can it be improved still?
>> int i = to!int(parse!float("0x1ap0"));
>
> parse!int("1a", 16);
I tried multiple combinations but not that one, thanks.

On 08/03/2011 10:44 AM, Stijn Herreman wrote:
> On 3/08/2011 2:32, Johann MacDonagh wrote:
>> On 8/2/2011 8:17 PM, Stijn Herreman wrote:
>>> std.conv does not support conversion from a hexadecimal string to an
>>> integer. Is there a technical reason for this limitation?
>>>
>>> This is the best I could do, can it be improved still?
>>> int i = to!int(parse!float("0x1ap0"));
>>
>> parse!int("1a", 16);
> I tried multiple combinations but not that one, thanks.

I am doing:
to!(int)(BigInt("0x1a").toInt());
toInt actually returns a long:
http://www.d-programming-language.org/phobos/std_bigint.html

It's kinda frustrating, but it's there.